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Ede4ka [16]
3 years ago
14

A Fair coin is tossed 4 times. What is the probability of not getting all heads?​

Mathematics
2 answers:
Soloha48 [4]3 years ago
5 0

Answer:

D

Step-by-step explanation:

p(not all heads) = 1 - p(all heads)

= p(all heads) = p(heads) * p(heads) * p(heads) * p(heads)

= 1/2* 1/2 * 1/2 * 1/2

p(all heads) = 1/16

Since our equation was originally 1 - p(all heads), substitute p(all heads)= 1/16 in the original equation

= 1 - 1//16

p (not all heads) = 15/16

Hope this helps!

Verdich [7]3 years ago
3 0

Answer:

15/16

Step-by-step explanation:

The probability of not getting all heads is

1 - P(all heads)

P (all heads) =P(heads) *  P(heads)* P(heads) * P(heads)

                      1/2* 1/2 * 1/2 * 1/2 = 1/16

1 - 1//16 = 15/16

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