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djverab [1.8K]
2 years ago
15

The number of micro-organisms in a culture triples every 3hrs. If there were 2 micro-organisms present at noon, how many were th

ere tomorrow the same time assuming that all micro-organisms survive?
Mathematics
1 answer:
Setler [38]2 years ago
3 0

There will be 13,122 micro-organisms present at noon the next day

The number of hours between noon today and noon tomorrow is 24 hours.

The micro-organisms triple every 3 hours. The first thing you need to do therefore, is to find the <u>number of 3 hour intervals in 24 hours. </u>

= 24 hours / 3

= 8 three hour intervals

The micro-organisms started with 2 and will triple every 3 hour intervals.

There are 8 three hour intervals so the number of micro-organisms at noon the next day is:

<em>= Beginning number of micro-organisms x 3 ^ number of three hour intervals </em>

= 2 x 3⁸

= 13,122 microorganisms

In conclusion, there will be 13,122 micro-organisms.

<em>Find out more at brainly.com/question/3390670.</em>

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Answer:

(x+5)²-10x²

Step-by-step explanation:

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x² +25

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3 years ago
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Find all real solutions and show work: <br> 2x^3-3x^2+18x-27=0
Amiraneli [1.4K]

Given:

The given equation is

2x^3-3x^2+18x-27=0

To find:

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Solution:

We have,

2x^3-3x^2+18x-27=0

It can be written as

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x=\dfrac{3}{2} and x=\pm\sqrt{-9}

We know that x=\pm\sqrt{-9} is an imaginary number because there is a negative sign under the square root.

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