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makvit [3.9K]
4 years ago
12

Which of the following correctly illustrates the conservation of mass for the reaction below?

Chemistry
1 answer:
ANEK [815]4 years ago
8 0
In order to apply the principle of conservation of mass to this reaction, we must prove that the mass on the left hand side is equivalent to the mass on the right hand side. In order to do this, we must first acquire the atomic masses of each substance involved. These are:
Fe - 56
O - 16

Now, we substitute these values into the equation:
4(56) + 3(2*16) = 2(56 * 2 + 16 * 3)
224 + 96 = 320
320 = 320

As we can see, the principle of conservation of mass holds true.
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A tissue that has the ability to contract is
bonufazy [111]
Muscle tissue

Explanation: Muscle tissue is a soft tissue that makes up most of the tissues in the muscles of the human muscular system. It is the only type of tissue that has cells with the ability to contract. Skeletal muscle tissue is attached to bones by tendons.
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3 years ago
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Which molecule does protein break up to?
melomori [17]

Answer:

enzymes

Explanation:

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3 years ago
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The Ksp of CaF2 is 4.0 x 10-11. What is the solubility of CaF2 in 0.10 M Ca(NO3)2? Give your answer using scientific notation an
Ilya [14]

Answer:

1.0\times 10^{-5} M is the solubility of CaF_2 in 0.10 M Ca(NO_3)_2.

Explanation:

Concentration of calcium nitrate = [Ca(NO_3)_2]=0.10 M

Ca(NO_3)_2\rightarrow Ca^{2+}+2NO_3^{-}

[Ca(NO_3)_2]=0.10 M=[Ca^{2+}]

Solubility product of the calcium fluoride = K_{sp}=4.0\times 10^{-11}

Solubility of calcium fluoride in calcium nitrate solution :

CaF_2\rightleftharpoons Ca^{2+}+2F^-

            (0.10+S)   (2S)

The expression of solubility is given by :

K_{sp}=[Ca^{2+}][F^-]^2

4.0\times 10^{-11}=(S+0.10)(2S)^2

Solving for S:

S=1.0\times 10^{-5} M

1.0\times 10^{-5} M is the solubility of CaF_2 in 0.10 M Ca(NO_3)_2.

3 0
3 years ago
Calculate the molality of a 20.0 percent by weight aqueous solution of nh4cl. (molecular weight: nh4cl = 53.5)
cestrela7 [59]
Unfortunately the data provided doesn't include the DENSITY of the ammonium chloride solution and molarity is defined as moles per volume. So without the density, the calculation of the molarity is impossible. But fortunately, there are tables available that do provide the required density and for a 20% solution by weight, the density of the solution is 1.057 g/ml.  
So 1 liter of solution will mass 1057 grams and the mass of ammonium chloride will be 0.2 * 1057 g = 211.4 g. The number of moles will then be 211.4 g / 53.5 g/mol = 3.951401869 mol. Rounding to 3 significant digits gives a molarity of 3.95.  
Now assuming that your teacher wants you to assume that the solution masses 1.00 g/ml, then the mass of ammonium chloride will only be 200g, and that is only (200/53.5) = 3.74 moles.   
So in conclusion, the expected answer is 3.74 M, although the correct answer using missing information is 3.95 M.
8 0
4 years ago
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What is the molarity of a solution containing 56 grams of solute in 959 ml of solution? (molar mass of solute = 26 g/mol)?
jolli1 [7]
26g --- 1 mol
56g --- X
X= 56/26 = 2,154 mol

959 ml = 959cm³ = 0,959dm³

C = n/V
C = 2,154/0,959
C = 2,246 mol/dm³
8 0
3 years ago
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