Answer:
0.852 mol
Explanation:
First we <u>convert 4.00 g of helium (He) into moles</u>, using its <em>molar mass</em>:
4.00 g ÷ 2 g/mol = 2 mol He
To answer this problem we can use<em> Avogadro's law</em>, which states that at constant pressure and temperature:
V₁n₂=V₂n₁
Where:
We <u>input the data</u>:
- 24.4 L * n₂ = 10.4 L * 2 mol
And <u>solve for n₂</u>:
the actual yield is the amount of Na₂CO₃ formed after carrying out the experiment
theoretical yield is the amount of Na₂CO₃ that is expected to be formed from the calculations
we need to first find the theoretical yield
2Na₂O₂ + 2CO₂ ---> 2Na₂CO₃ + O₂
molar ratio of Na₂O₂ to Na₂CO₃ is 2:2
number of Na₂O₂ moles reacted is equal to the number of Na₂CO₃ moles formed
number of Na₂O₂ moles reacted is - 7.80 g / 78 g/mol = 0.10 mol
therefore number of Na₂CO₃ moles formed is - 0.10 mol
mass of Na₂CO₃ expected to be formed is - 0.10 mol x 106 g/mol = 10.6 g
therefore theoretical yield is 10.6 g
percent yield = actual yield / theoretical yield x 100%
81.0 % = actual yield / 10.6 g x 100 %
actual yield = 10.6 x 0.81
actual yield = 8.59 g
therefore actual yield is 8.59 g
1) endothermic
2)exotgermic
3)exotgermic
7.2 mol H × (1 mol H_2SO_4/2 mol H) = 3.6 mol H_2SO_4
Answer:
The scientific method is a method of research in which a problem is identified, relevant data are gathered. Also hypothesis is made from this data, and the hypothesis is empirically tested.
Explanation: