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sesenic [268]
3 years ago
5

Describe briefly the changes from the control values in the MEAN values for volume, specific gravity and NaCl after drinking pur

e water. Based on the specific gravity measurements, is the urine isosmotic, hyperosmotic or hypoosmotic to the fluids of the body. Explain using physiological relevance.
Chemistry
1 answer:
Yuri [45]3 years ago
8 0

Answer:

As specific gravity is defined as weight per unit volume,so urine is the less dense fluid,so urine will be in hyperosmotic category.

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For the reaction C2H4(g) + H2O(g) --> CH3CH2OH(g)
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Explanation :

As we know that,

\Delta G^o=\Delta H^o-T\Delta S^o

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\Delta H^o = standard enthalpy = -45.6 kJ = -45600 J

\Delta S^o = standard entropy = -125.7 J/K

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Now put all the given values in the above formula, we get:

\Delta G^o=(-45600J)-(262.0K\times -125.7J/K)

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The relation between the equilibrium constant and standard Gibbs free energy is:

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R = gas constant  = 8.314 J/K.mol

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K = equilibrium constant = ?

Now put all the given values in the above formula, we get:

-12666.6J=-(8.314J/K.mol)\times (262.0K)\times \ln k

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