How do the isotopes of an element differ?

Chemistry

1 answer:

ra1l [238]2 years ago

5 0

They have different neutron number and thus different mass number, but they are the same element.

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240 g of water (specific heat = 4.186 J/g°C, initial temperature = 20°C) is mixed with an

ivolga24 [154]

The answer for this would be 69.6

3 0

2 years ago

a book with a mass of 1 kg is dropped from a height of 3 m. what is the potential energy of the book when it reaches the floor?

mafiozo [28]

Well, first of all, the formula for finding potential energy is;
PE=mgh
Where; m is the mass
g is the gravitational force or acceleration due to gravity
h is the height.
Anyway, according to the question, the mass is 1kg, the acceleration due to gravity has a constant value of 10ms² . And the height is 3m. Now you just have to use all these in the formula. So;
mgh= 1 x 10 x 3. That will be 30. And the unit of potential energy is Joule. So the answer is 30 joules. Hope i helped. Have a nice day.

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2 years ago

In general, ionic compounds are hard solids at ambient temperatures but they shatter fairly easily. How do these two properties

lord [1]

Ionic or electrovalent compounds support the theory of ionic bonding because they are compounds composed of charged particles formed when an atom gains or loses electrons.

Electrovalent compounds posses:

High boiling and melting points.
Form crystals.

<h3>What is ionic bonding?</h3>

This is the transfer of valence electrons from metals to non metals to form ionic compounds. It also refers to a chemical bond formed between two ions with opposite charges.

Learn more about ionic compounds:

brainly.com/question/18246121

7 0

2 years ago

What is the mass of a sample of water that takes 2000 kJ of energy to boil into steam at 373 K. The latent heat of vaporization

zzz [600]

Answer:

$\boxed{\text{889 g}}$

Explanation:

The formula relating the mass m of a sample and the heat q to vaporize it is

q = mL, where L is the latent heat of vaporization.

$\begin{array}{rcl}2000 \times 10^{3} \text{ J} & = & m \times \dfrac{2.25 \times 10^{6} \text{ J}}{\text{1 kg}}\\\\m & = & \dfrac{2000 \times \times 10^{3}\text{ kg}}{2.25 \times 10^{6}}\\ & = & \text{0.889 kg}\\\\ & = & \text{889 g}\\\end{array}\\\text{The mass of water is $\boxed{\textbf{889 g}}$}$