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3 years ago

James mixed Barium and oxide. what does he get? how does it work?

Chemistry

1 answer:

kherson [118]3 years ago

5 0

Answer: Barium Oxide

We know that:

James mixed Ba + O²

Now, let's see what will happen when he does mix it.

The Barium will give it's electrons up to the oxide.

The Oxide and Barium will both reach noble gas status.

In the end, James will get Barium Oxide.

Best of Luck!

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In which pair would both compounds have the same empirical formula? A. H2O and H2O2 B. BaSO4 and BaSO3 C. FeO and Fe2O3 D. C6H12

Kazeer [188]

The pair of both compounds that have the same empirical formula are C6H12O6 and HC2H3O2. The answer is letter D. H2O and H2O2, BaSO4 and BaSO3 and FeO and Fe2O3 do not have the same empirical formula.

4 0

3 years ago

An herbicide contains only C, H, Cl, and N. The complete combustion of a 200.0 mg sample of the herbicide in excess oxygen produ

MAVERICK [17]

Answer:

%C = 56,1%

%H = 5,5%

%Cl = 27,6%

%N = 10,8%

Explanation:

The moles of CO₂ are the same than moles of C in the herbicide.

Moles of H₂O are ¹/₂ of moles of H in the herbicide.

Moles of CO₂ are obtained using:

n = PV/RT

Where, in STP: P is 1 atm; V is 0,2092L; R is 0,082atmL/molK; T is 273 K

moles of CO₂ are: 9,345x10⁻³ mol≡ mol of C×12,01g/mol = 0,1122 g of C ≡ 112,2mg of C

In the same way, moles of H₂O are 5,450x10⁻³mol×2 =0,1090 mol of H×1,01g/mol = 0,0110 g of H ≡ 11,0mg of H

As you have 55,14 mg of Cl, the mg of N are:

200,0mg - 112,2 mg of C - 11,0 mg of H - 55,14 mg of Cl = 21,66 mg of N

Thus, precent composition of the herbicide is:

%C = $\frac{112,2 mgC}{200,0mg}$ ×100 = 56,1%C

%H = $\frac{11,0 mgH}{200,0mg}$ ×100 = 5,5%H

%Cl = $\frac{55,14 mgCl}{200,0mg}$ ×100 = 27,6%Cl

%N = $\frac{21,66 mgN}{200,0mg}$ ×100 = 10,8%N

I hope it helps!

3 0

3 years ago

Consider the following intermediate chemical equations.

vfiekz [6]

Answer:

-250.3kJ

Explanation:

Based in the reactions and using -Hess's law-:

(1) P₄(s) + 6 Cl₂(g) → 4PCl₃(g) ΔH₁ = -4439kJ

(2) 4PCl₅(g) → P₄(s) + 10Cl₂ ΔH₂ = 3438kJ

The sum of (1) + (2) is:

4PCl₅(g) → 4PCl₃(g) + 4 Cl₂ ΔH = -4439kJ + 3438kJ = -1001kJ

Dividing this reaction in 4:

PCl₅(g) → PCl₃(g) + Cl₂ ΔH = -1001kJ / 4 = -250.3kJ

8 0

3 years ago

Do electric or magnetic fields affect the x-rays?

Levart [38]

Electric and magnetic fields do not affect xrays as they only affect charged particles and xrays have no charge

hope that helps

3 0

3 years ago

Inclined planes reduce the amount of effort needed to move an object, but increases

QveST [7]

Inclined planes reduce the amount of effort needed to move an object, but increases the length of the ramp.

Explanation:

Mechanical advantage is the measure of amount of effort needed to move an object. The mechanical advantage can be calculated as the ratio of length of ramp to the height of ramp for an inclined plane.

As it is known that an object can be easily moved on an inclined plane than on a vertical plane, this is because, the inclined plane provides greater output force. But in that case, the effort required will be reduced with the cost of increasing the distance of the movement of object.

In other terms , the ramp's length of inclined planes has to get increased in order to reduce the amount of effort needed to move an object. This is because as the mechanical advantage has length of the ramp in the numerator, with the increase in numerator value or length value the mechanical advantage will also increase.

8 0

3 years ago