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3 years ago

{3} is a subset of {1, 2, 4, 5, 6} ?

1 answer:

5 0

No, a set is only a subset of another set if it only contains elements contained in the original set.
3 isn't an element of {1,2,4,5,6}, so {3} isn't a subset of {1,2,4,5,6}.

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In the field of quality control, the science of statistics is often used to determine if a process is "out of control." Suppo

Usimov [2.4K]

Answer:

a) P=0.0225

b) P=0.057375

Step-by-step explanation:

From exercise we have that 15% of items produced are defective, we conclude that probabiity:

P=15/100

P=0.15

a) We calculate the probabiity that two items are defective:

P= 0.15 · 0.15

P=0.0225

b) We calculate the probabiity that two of three items are defective:

P={3}_C_{2} · 0.85 · 0.15 · 0.15

P=\frac{3!}{2!(3-2)!} · 0.019125

P=3 · 0.019125

P=0.057375

6 0

3 years ago

While conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modem

Kitty [74]

Answer:

We conclude that this is an unusually high number of faulty modems.

Step-by-step explanation:

We are given that while conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modems.

The probability of obtaining this many bad modems (or more), under the assumptions of typical manufacturing flaws would be 0.013.

Let p = population proportion.

So, Null Hypothesis, $H_0$ : p = 0.013 {means that this is an unusually 0.013 proportion of faulty modems}

Alternate Hypothesis, $H_A$ : p > 0.013 {means that this is an unusually high number of faulty modems}

The test statistics that would be used here One-sample z-test for proportions;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion faulty modems= $\frac{10}{367}$ = 0.027

n = sample of modems = 367

So, the test statistics = $\frac{0.027-0.013}{\sqrt{\frac{0.013(1-0.013)}{367} } }$

= 2.367

The value of z-test statistics is 2.367.

Since, we are not given with the level of significance so we assume it to be 5%. Now at 5% level of significance, the z table gives a critical value of 1.645 for the right-tailed test.

Since our test statistics is more than the critical value of z as 2.367 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that this is an unusually high number of faulty modems.

6 0

3 years ago

PLEASE, IT IS URGENT!!!!!!!!!!!!!!!!

sasho [114]

Convert the timing into hours only:
11:15 = 11.25h
9:45 = 9.75h
11:45 = 11.75h
7:45 = 7.75h
10:45 = 10.75h

To find the average, we need to find the middle of these timing:
11.25 + 9.75 + 11.75 + 7.75 + 10.75 = 51.25

51.25 ÷ 5 = 10.25h = 10:15 am

------------------------------------------------------------------------
Answer: The average time it docks is 10:15 am.
------------------------------------------------------------------------

5 0

2 years ago

HELP!!! GIVE WHOEVER BRAINLIEST !!!

andrey2020 [161]

Answer:

Step-by-step explanation:

The opposite of x is -x

And the opposite of -6 is 6

So -x+6 is the inverse

8 0

2 years ago

Explain why the mean without the outliner could be a better description of the data set than the mean with the outliner.

lions [1.4K]

Sometimes the outlier, if it's too large, can throw off the mean, making it larger and smaller, so it isn't as accurate

sorry if this doesnt make sense if you need me to explain it more I will

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3 years ago

Read 2 more answers