The correct answer for the question that is being presented above is this one: "(d) the magnitude of the normal force on the box from the ramp." A box is on a ramp that is at angle θ to the horizontal. As θ is increased from zero, and before the box slips, do the following increase, decrease, or remain the same and <span> the magnitude of the normal force on the box from the ramp.</span>
The answer is D. To the left with speed 2v
Answer:
Part a)

Part b)

Part c)

Explanation:
Part a)
As we know that the speed of light is given as


now the frequency of the light is given as

so we have


Part b)
Position of Nth maximum intensity on the screen is given as

so here we know for 3rd order maximum intensity

n = 3
L = 1.4 m


Part c)
angle of third order maximum is given as



Using the appropriate approximations:
dx/L = mλ
d = slit separation
x = fringe spacing
L = distance between slits and screen
m = some integer, used to determine the distance from the central bright fringe to another bright fringe
We don't really need a value for m because we're calculating the distance between any pair of consecutive fringes. Let's just set m = 1
Given values:
d = 1.0mm
L = 2.0m
λ = 480nm
Substitute the terms in the equation with our given values and solve for x:
1.0*10⁻³*x/2 = 480*10⁻9
<h3>x = 0.96mm</h3>
The angular momentum of a rotation object is the product of its moment of inertia and its angular velocity:
L = Iω
L is the angular momentum, I is the moment of inertia, and ω is the angular velocity.
Apply the conservation of angular momentum. The total angular momentum before disks A and B are joined is:
L_{before} = (3.3)(6.6) + B(-9.3)
L_{before} = -9.3B+21.78
where B is the moment of inertia of disk B.
The total angular momentum after the disks are joined is:
L_{after} = (3.3+B)(-2.1)
L_{after} = -2.1B-6.93
L_{before} = L_{after}
-9.3B + 21.78 = -2.1B - 6.93
B = 4.0kg·m²
The moment of inertia of disk B is 4.0kg·m²