Question

In the reaction H2SO4 + 2 NaOH -> Na2SO4 + 2H2O, an equivalence point occurs when 32.23 mL of 0.2423 M NaOH is added to a 37.21 mL portion of H2SO4. What is the [H2SO4]?

Answer 1

The reaction H2SO4 + 2 NaOH -> Na2SO4 + 2H2O applies to an acid-base titration.
            moles NaOH = c · V = 0.2423 mmol/mL · 32.23 mL = 7.809329 mmol
            moles H2SO4 = 7.809329 mmol NaOH · 1 mmol H2SO4 / 2 mmol NaOH = 3.9046645 mmol
Hence
            [H2SO4]= n/V = 3.9046645 mmol / 37.21 mL = 0.1049 M
The answer to this question is  [H2SO4] = 0.1049 M