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Sunny_sXe [5.5K]

2 years ago

13

Based on the rocks they contain, predict how Devils Tower and the Giant's Causeway formed. Explain your answer in terms of extru

sive and intrusive rocks and the observations you made of both formations.

2 answers:

inessss [21]2 years ago

5 0

Answer:

i'm not sure, so sorry

Explanation:

ZanzabumX [31]2 years ago

3 0

I’m not sure either I’m really sorry

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How many moles of sodium hydroxide are there in 1.0mL of 2.0M NaOH

kvasek [131]

To find the moles, you can use the following formula

moles= Molarity x Liters

Molarity= 2.0 M
Liters= 0.0010 Liters ---------------->>>>>>>>>> 1.0 mL= 0.0010 Liters

moles= 2.0 M x 0.0010 Liters= 0.0020 moles

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2 years ago

Which ecosystem is most resilient to change due to its high diversity?

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Answer:

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Explanation:

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3 years ago

5. __NH3 + __O2 >>>>>__ NO +__ H20

inn [45]

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3 years ago

Gold has a density of 1,200 lb./ft. What is the density of gold in g/em? For conversion factors use I lb. 453.6 g, and l inch-2.

Jlenok [28]

<u>Answer:</u> The density of gold in $g/cm^3$ is $19.22g/cm^3$

<u>Explanation:</u>

Density is defined as the ratio of mass of the object and volume of the object. Mathematically,

$\text{Density}=\frac{\text{Mass of the object}}{\text{Volume of the object}}$

We are given:

Density of gold = $1200lb/ft^3$

Using conversion factors:

1 lb = 453.6 g

1 feet = 12 inches

1 inch = 2.54 cm

Converting given quantity into $g/cm^3$ , we get:

$\Rightarrow (\frac{1200lb}{ft^3})\times (\frac{453.6g}{1lb})\times (\frac{1ft}{12inch})^3\times (\frac{1inch}{2.54cm})^3\\\\\Rightarrow 19.22g/cm^3$

Hence, the density of gold in $g/cm^3$ is $19.22g/cm^3$

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3 years ago

What is the displacement of the particle in the time interval 7 seconds to 8 seconds?

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Answer:

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3 years ago