Answer:
Explanation:
A solution of a weak base and its conjugate acid is a buffer.
The equation for the equilibrium is
The Henderson-Hasselbalch equation for a basic buffer is
![\text{pOH} = \text{p}K_{\text{b}} + \log\dfrac{[\text{BH}^{+}]}{\text{[B]}}](https://tex.z-dn.net/?f=%5Ctext%7BpOH%7D%20%3D%20%5Ctext%7Bp%7DK_%7B%5Ctext%7Bb%7D%7D%20%2B%20%5Clog%5Cdfrac%7B%5B%5Ctext%7BBH%7D%5E%7B%2B%7D%5D%7D%7B%5Ctext%7B%5BB%5D%7D%7D)
Data:
[B] = 0.400 mol·L⁻¹
[BH⁺] = 0.250 mol·L⁻¹
Kb = 4.4 × 10⁻⁴
Calculations:
(a) Calculate pKb
pKb = -log(4.4× 10⁻⁴) = 3.36
(b) Calculate the pH
Answer:
d
Explanation:
its right to be sydinachiondical
I choose the answer:d.potassium nitrate.
Answer:
1.12 moles
Explanation:
To find the amount of moles, you need to use the Ideal Gas Law:
PV = nRT
In this equation,
-----> P = pressure (atm)
-----> V = volume (L)
-----> n = moles
-----> R = Ideal Gas constant (0.08206 atm*L/mol*K)
-----> T = temperature (K)
After converting the temperature from Celsius to Kelvin, you can plug the given values into the equation and solve for "n".
P = 1.00 atm R = 0.08206 atm*L/mol*K
V = 25.0 L T = 0. °C + 273 = 273 K
n = ? moles
PV = nRT
(1.00 atm)(25.0 L) = n(0.08206 atm*L/mol*K)(273 K)
25.0 = n(22.4)
1.12 = n
Answer: Option (e) is the correct answer.
Explanation:
A compound that will dissociate in water or an aqueous solution to give hydrogen ions(
) is known as an acidic substance.
When RbH is dissolved in aqueous solution then it dissociates as follows.
.
is non-polar in nature. So, it will not dissociate into ions when dissolved in an aqueous solution.
will also remain neutral and does not dissociate into ions.
when dissolved in water then it dissociates as follows.
Whereas when HF is dissolved in aqueous solution then the reaction will be as follows.
Thus, we can conclude that out of the given options HF is the compound which will produce an acidic aqueous solution.
