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Aloiza [94]
3 years ago
11

If the half-life of a radionulide is 1 month, what percent remains after 4 months?

Chemistry
1 answer:
Aliun [14]3 years ago
6 0

Answer:

6.25% of the original amount

Explanation:

half-life means that half is gone for every certain period of time. Because the half life is 1 month, only half of the 'radionulide' is left every month.

after 1 month= 50%

after 2 months= 25%

after 3 months= 12.5%

after 4 months= 6.25%

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Draw the ground-state electronic configuration for Mg.
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(Ne)3s2

Explanation:

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2. What effect does adding a neutron have on the atom’s mass?
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In an atom the number of electron is what as the number of protons???​
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7 0
2 years ago
Alpha helices are a type of secondary structure in proteins. What is the length of a 27.0 kDa single‑stranded α‑helical protein
iogann1982 [59]

Answer : The  length of protein will be, 36.8 A⁰

Explanation :

First we have to calculate the amino acid residue.

\text{Amino acid residue}=\frac{\text{Length of single strand of protein}}{\text{Mean residue mass}}

Given:

Length of single strand of protein = 27.0 kDa

Mean residue mass = 110 Da

\text{Amino acid residue}=\frac{27.0kDa}{110Da}=\frac{27000Da}{110Da}=245.4

Now we have to calculate the number of turns in protein.

\text{Number of turns in protein}=\frac{\text{Amino acid residue}}{3.6\text{amino acid per turn of the alpha-helix}}

As there are 3.6 amino acid per turn of the alpha-helix.

\text{Number of turns in protein}=\frac{245.4}{3.6}=68.17

Now we have to calculate the length of the protein.

\text{Length of protein}=\text{Number of turns in protein}\times \text{Length of each turn}

As, we know that the length of each turn = 0.54 A⁰

\text{Length of protein}=68.17turns\times 0.54\AA=36.8\AA

Thus, the length of protein will be, 36.8 A⁰

8 0
3 years ago
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