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Aloiza [94]
3 years ago
11

If the half-life of a radionulide is 1 month, what percent remains after 4 months?

Chemistry
1 answer:
Aliun [14]3 years ago
6 0

Answer:

6.25% of the original amount

Explanation:

half-life means that half is gone for every certain period of time. Because the half life is 1 month, only half of the 'radionulide' is left every month.

after 1 month= 50%

after 2 months= 25%

after 3 months= 12.5%

after 4 months= 6.25%

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HELP ASAP!!
Ksju [112]
109/8.56=12.7
50+12.7
V=62.7

Mass= Volume x Density so i divided the mass and density to get the volume. and afterwards i would just add it to the mass to get my final answer

4 0
3 years ago
Read 2 more answers
Which substance has the greatest of elements?<br> Sugar 45 elements
Nutka1998 [239]

Answer: Which elements are found in the greatest number of substances?

...

Chemical Name Sucrose

Chemical Formula C12H22O11

Number of Elements 3

Name of Elements Carbon, Hydrogen, Oxygen

Number of Atoms 45

Explanation:

7 0
3 years ago
Please please help me please please
uranmaximum [27]

Answer: 1. A, 2.B, 3. D, 4. B, 5. C

Explanation:

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5 0
3 years ago
Iron ore exists as Fe2O3. In order to remove the oxygen and generate pure iron, the oxygen must be transferred to another molecu
Svetllana [295]
The answer would be c
4 0
2 years ago
A fluid occupying has a mass of 4mg. Calculate its density and specific volume in SI, EE, and BG units.
kondaur [170]

The question is incomplete, complete question is:

A fluid occupying 3.2 m^3 of volume has a mass of 4 Mg. Calculate its density and specific volume in SI, EE, and BG units.

Explanation:

1) Mass of liquid = m = 4 Mg = 4 × 1,000 kg = 4,000 kg

(1 Mg = 1000 kg)

Volume of the fluid = V = 3.2 m^3

Density of the fluid = D

D=\frac{m}{V}=\frac{4,000 kg}{3.2 m^3}=1,250 kg/m^3

Specific volume is the reciprocal of the density :

V_{specific}=\frac{1}{Density}

Specific volume of the fluid = S_v

S_v=\frac{1}{D}=\frac{1}{1,250 kg/m^3}=0.0008 m^3/kg

2)

Density of the fluid in English Engineering units  = D (lb/ft^3)

1 kg = 2.20462 lb

1 m = 3.280 ft

D=\frac[1,250\times 2.20462 lb}{(3.280 ft)^3=78.95 lb/ft^3

Specific volume of the fluid :

=\frac{1}{78.95 lb/ft^3}=0.0127 ft^3/lb

3)

Density of the fluid in British Gravitational System units  = D (slug/ft^3)

1 kg = 0.06852 slug

1 m = 3.280 ft

D=\frac[1,250\times 0.0685218 slug}{(3.280 ft)^3=2.43 slug/ft^3

Specific volume of the fluid :

=\frac{1}{2.43 slug/ft^3}=0.412 ft^3/slug

7 0
3 years ago
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