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2 years ago

People in the chemical industry supply man-made chemicals essential to human needs and desires. True or false

Chemistry

1 answer:

Paladinen [302]2 years ago

3 0

true you have to consider that like thats true man im just tryna waste space

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s) Suppose we now collect hydrogen gas, H2(g), over water at 21◦C in a vessel with total pressure of 743 Torr. If the hydrogen g

Elenna [48]

This is an incomplete question, here is a complete question.

Suppose we now collect hydrogen gas, H₂(g), over water at 21°C in a vessel with total pressure of 743 Torr. If the hydrogen gas is produced by the reaction of aluminum with hydrochloric acid:

$2Al(s)+6HCl(aq)\rightarrow 2AlCl_3(aq)+3H_2(g)$

what volume of hydrogen gas will be collected if 1.35 g Al(s) reacts with excess HCl(aq)? Express your answer in liters.

Answer : The volume of hydrogen gas that will be collected is 1.85 L

Explanation :

First we have to calculate the number of moles of aluminium.

Given mass of aluminium = 1.35 g

Molar mass of aluminium = 27 g/mol

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

$\text{Moles of aluminium}=\frac{1.35g}{27g/mol}=0.05mol$

The given chemical reaction is:

$2Al(s)+6HCl(aq)\rightarrow 2AlCl_3(aq)+3H_2(g)$

As, hydrochloric acid is present in excess. So, it is considered as an excess reagent.

Thus, aluminium is a limiting reagent because it limits the formation of products.

By Stoichiometry of the reaction:

2 moles of aluminium produces 3 moles of hydrogen gas

So, 0.005 moles of aluminium will produce = $\frac{3}{2}\times 0.05=0.0750mol$ of hydrogen gas

Now we have to calculate the mass of helium gas by using ideal gas equation.

PV = nRT

where,

P = Pressure of hydrogen gas = 743 Torr

V = Volume of the helium gas = ?

n = number of moles of hydrogen gas = 0.075 mol

R = Gas constant = $62.364\text{ L Torr }mol^{-1}K^{-1}$

T = Temperature of hydrogen gas = $21^oC=[21+273]K=294K$

Now put all the given values in above equation, we get:

$743Torr\times V=0.075mol\times 62.364\text{ L Torr }mol^{-1}K^{-1}\times 294K\\\\V=1.85L$

Hence, the volume of hydrogen gas that will be collected is 1.85 L

8 0

3 years ago

As water molecules move through the hydrological cycle, water both gains and loses energy. In which case would the water be losi

Triss [41]

Condensation. I just completed the test

5 0

2 years ago

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Choose the number for the word the description matches.

rosijanka [135]

Area where magnet is present - magnetic feild
the 2 ends are the poles
magnetic in presence is temporary and always magnetic is permanent
opposites is dipolar<span />

5 0

3 years ago

Which element is in Group 2 and Period 7 of the Periodic Table?

miss Akunina [59]

Answer:

A) Radium

i don't think that group 2 has period 7, it has only up to period 6 so it's probably Radium :))

3 0

3 years ago

If the density of water is 1.000 g/ml, what is the mass in grams of 1.000 gallons of water?

Hunter-Best [27]

Recall that 1 gallon = 3.785 L, and 1 L = 1000 mL, so to calculate volume in millilitres, multiply by 3.785 and 1000, resulting in 3785 mL. Next, multiply volume by density to calculate mass (Density = Mass/Volume), so 3785 mL * 1.000 g / mL = 3785 g of water.

5 0

3 years ago