Answer:
SeCl₆ < SeF₂ < SeO₂
Explanation:
To determine the order of the bond angle of the compound, we need to determine the hybridization of each compound given.
For:
SeO₂, The hybridization is sp² because the Se is doubly bonded to O at both sides and Se contains a lone pair of electrons.
SeCl₆, Se is attached to six different Cl atoms via a single bond in a hexagonal shape. Thus, SeCl₆ hybridization is sp³d²
SeF₂, Here, Se is singly bonded to F atoms on both sides and Se contains a lone pair of electrons. The hybridization is sp³
Therefore, the bond angle in sp² = 120°, sp³ = 109.8°, sp³d² = 90°
Hence, the order is: SeCl₆ < SeF₂ < SeO₂
Pass the mixture through a screen to allow the salt and pepper to pass through but traps the pebbles. Mix the salt and pepper with water to dissolve the salt and filter it to get the pepper.
Answer:
18 is a
19 is c
20 i am not sure
Explanation:
18)nucleus contains protons and neutrons
Answer:
V₁ = 0.342 M
Explanation:
Given data:
Volume of HClO₄ = 15.00 mL
Volume of NaOH = 25.64 mL
Molarity of NaOH = 0.2000 M
Molarity of HClO₄ = ?
Solution:
Formula:
M₁V₁ = M₂V₂
V₁ = M₂V₂ /M₁
V₁ = 0.2000 M ×25.64 mL /15.00 mL
V₁ = 5.128 M. mL /15.00 mL
V₁ = 0.342 M
Answer: KI, LiBr, MgS,GaN
Explanation:
Ionic sizes are the deciding factor in lattice energy. The smaller the ion, the higher the lattice energy. Since K+> Li+ and I- is larger than Br-, LiBr will have a higher lattice energy. The size of the sulphide ion is much smaller than the nitride ion but the Gallium is much smaller due to lanthanide contraction hence the answer.
