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sveta [45]
3 years ago
12

The density of the fat tristearin is 0.95 g cm−3 . Calculate the change in molar Gibbs energy of tristearin when a deep-sea crea

ture is brought to the surface (p = 1.0 atm) from a depth of 2.0 km. To calculate the hydrostatic pressure, take the mean density of water to be 1.03 g cm−3 .
Chemistry
1 answer:
KatRina [158]3 years ago
8 0

The formula for the change in Gibbs energy of a solid is:

ΔG = Vm ΔP

where, ΔG is change in Gibbs, Vm is molar volume, ΔP is change in pressure

ΔP = P(final) – P(initial)

P(final) = 1 atm = 101325 Pa

P(initial) = ρ_water *g *h = (1030 kg/m^3) * 9.8 m/s^2 * 2000 m = 20188000 kg m/s^2 = 20188000 Pa

Vm = (950 kg/m^3) * (1000 mol / 891.48 kg) = 1065.64 mol/m^3

 

So,

ΔG = (1065.64 mol/m^3) * (101325 Pa - 20188000 Pa)

<span>ΔG = -21405164347 J = -21.4 GJ</span>

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A fuel tank holds 22.3 gallons of gasoline. If the density is 0.8206 g/mL, what is the mass in kilograms of gasoline in a full t
7nadin3 [17]

Answer:

m=69.3kg

Explanation:

Hello!

In this case, since the density is computed by dividing the mass of the substance by its occupied volume (d=m/V), we first need to realize that 0.8206 g/mL is the same to 0.8206 kg/L, which means we first need to compute the volume in L:

V=22.3gal*\frac{3.78541L}{1gal}=84.415L

Then, solving for the mass in d=m/V, we get m=d*V and therefore the mass of gasoline in that full tank turns out:

m=0.8206g/L*84.415L\\\\m=69.3kg

Best regards!

8 0
3 years ago
A rectangular solid has a length of 3 cm a height of 4 cm and a width of 5 cm what is the solid volume ?
andrew11 [14]
Volume is 60 and the area is 94 have a great day
3 0
3 years ago
Oxygen and hydrogen form the polyatomic hydroxide ion. What is its charge?
prohojiy [21]

Answer:

negative

the chage on hydroxide ions os negative

4 0
3 years ago
Read 2 more answers
24. 00 ml of a 0. 25 m naoh solution is titrated with 0. 10m hcl. What is the ph of the solution after 24. 00 ml of the hcl has
12345 [234]

pH of the solution after 24. 00 ml of the hcl has been added is 12.87

millimoles NaOH = mL x M = 24.00 mL x 0.25 M = 6.00

millimoles HCl = 24.00 mL x 0.10 M = 2.40

total volume = 48.00 mL

.................................NaOH + HCl ==>NaCl + H2O

initial.........................6.00.........0............0.........0

added.....................................2.40............................

change.................... -2.40......-2.40.........+2.40.... +2.40

equilibrium.................3.60.........0..............2.40.......2.40

The NaCl contributes nothing to the pH of the final solution. The pH is determined by the excess of NaOH present. (NaOH) = millimoles/mL = 3.60/48.00 = 0.075 M = (OH^-)

pOH = -log (OH^-). Then

pOH = -log (0.075)

pOH =1.1249

As we know,

pH + pOH = pKw = 14.00

pH=14-pOH

pH=14-1.1249

pH=12.87

<h3>What is pH?</h3>

pH is a logarithmic measure of an aqueous solution's hydrogen ion concentration. pH = -log[H+], where log is the base 10 logarithm and [H+] is the concentration of hydrogen ions in moles per liter.

The pH of an aqueous solution describes how acidic or basic it is, with a pH less than 7 being acidic and a pH greater than 7 being basic. A pH of 7 is regarded as neutral (e.g., pure water). pH values typically range from 0 to 14, though very strong acids may have a negative pH and very strong bases may have a pH greater than 14.

Learn more about pH:

brainly.com/question/491373

#SPJ4

7 0
1 year ago
A container of gas has a volume of 3.5 L and a pressure of 0.8 atm. Assuming the temperature remains constant, what volume of ga
vovikov84 [41]
<h3>Answer:</h3>

5.6 L

<h3>Explanation:</h3>

We are given;

  • Initial volume, V1 = 3.5 L
  • Initial pressure, P1 = 0.8 atm
  • Final pressure, P2 = 0.5 atm

We are required to calculate the final volume;

  • According to Boyle's law, the volume of a fixed mass of a gas and the pressure are inversely proportional at a constant temperature.
  • That is; P α 1/V
  • Mathematically, P=k/V
  • At two different pressure and volume;

           P1V1 = P2V2

In this case;

Rearranging the formula;

V2 = P1V1 ÷ P2

     = (0.8 atm × 3.5 L) ÷ 0.5 atm

    = 5.6 L

Therefore, the resulting volume is 5.6 L

7 0
3 years ago
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