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Mazyrski [523]
3 years ago
13

In triangle STU, s = 9 cm, t = 15 cm, and m angle U = 37 degrees. Find u.

Mathematics
2 answers:
erik [133]3 years ago
6 0

Answer:

1.) A 39 degrees

2.) B 36 degrees

3.) B 43.8

4.) B 96.68

5.) C 169.3 ft

6.) C 9.5 cm

7.) X = 8.4 cm

8.) X= 2879.4 m

Step-by-step explanation:

liq [111]3 years ago
4 0
We can solve the length of u using Laws of Cosine since we are given with lengths of two side and one angle.
The solution is shown below:
cos U =( s²+t²-u²)/2st
cos 37°= (9²+15²-u²)/2*9*15
0.79863*270=306-u²
u²=306-215.63
u=9.5 units
Therefore, the length of u is 9.5cm.

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Step-by-step explanation:

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divide 9 by 12

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3 years ago
What is lim x→3 x^2 - x - 6/ x - 3
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Explanation:

If we plugged x = 3 into the expression, then we'd get x-3 = 3-3 = 0 in the denominator. That's not allowed. But we can simplify first

x^2-x-6 factors to (x-3)(x+2). The key here is that (x-3) is a factor. It cancels with the x-3 in the denominator

So, \frac{x^2-x-6}{x-3} = \frac{(x-3)(x+2)}{x-3} = x+2

Allowing us to say,

\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = \lim_{x \to 3}\frac{(x-3)(x+2)}{x-3}\\\\\\\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = \lim_{x \to 3}(x+2)\\\\\\\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = 3+2\\\\\\\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = 5\\\\\\

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4 years ago
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Answer:

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