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kondaur [170]
3 years ago
14

A customer wants you to enlarge a photo to 2 /34 its current height. The photo’s current height is 3 1/4 inches. What should its

enlarged height be, in inches?
Mathematics
2 answers:
alex41 [277]3 years ago
5 0

Answer:

8 15/16 inches

Step-by-step explanation:

just multiply 2 3/4 by 3 1/4

avanturin [10]3 years ago
3 0

<u>Answer:</u>

8.94 inches or 8\frac { 1 5 } { 1 6 } inches

<u>Step-by-step explanation:</u>

We know that the current height of the photo is 3\frac{1}{4} inches and the customer wants it to be enlarged by a factor of 2\frac{3}{4} its current height.

3\frac { 1 } { 4 } = 3.25

2 \frac { 3 } { 4 } = 2.75

To find the enlarged height, we will multiply the scale factor with the photo's current height.

Enlarged height = 3.25 \times 2.75 = 8.94 inches or [tex] 8\frac { 1 5 } { 1 6 } inches

<u></u>

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See diagram
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minus original aera
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4a²+24a+35-35=4a²+24a


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2 years ago
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valkas [14]

2.57*10^4 is 1,000,000 times more than 2.57*10^-1

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lana66690 [7]

The answers to the blanks are

1. 600,

2. 120,

3. 120,

4. 180.

Explanation:

  • The fence means perimeter around the court. So a tennis court's perimeter is 600 feet fence. The perimeter of a rectangle is 2 times the sum of the rectangle's length and the rectangle's width.
  • It is given that length equals 60 more than width i.e. l = w + 60, where l is the length of the court and w is the width of the court.
  • The perimeter of a court = 600 = 2 (l + w) = 2l + 2w = 2 (w +60) + 2w,                                                                                                     this becomes, 2w + 120 + 2w = 600; 4w = 480, w = 120.
  • Since l = w + 60, l = 120 + 60 = 180. So length of a court is 180 feet and the width of a court is 120 feet.

6 0
3 years ago
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