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Shtirlitz [24]
4 years ago
9

A sinusoidal wave travels along a string. The time for a particular point to move from maximum displacement to zero is 0.17 s. W

hat are the (a) period and (b) frequency? (c) The wavelength is 1.5 m; what is the wave speed?
Physics
1 answer:
11Alexandr11 [23.1K]4 years ago
8 0

Answer:

31

Explanation:

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The strength of a magnetic field around a wire carrying a current of 20 A is 0.004 T. What is the strength of the
Alex777 [14]

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D. 0.008 T

Explanation:

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What is a lenticular (S0) galaxy? A galaxy with a disk and central bulge like a spiral galaxy, but with no spiral arms A galaxy
RSB [31]

Answer:

A galaxy with a disk and central bulge like a spiral galaxy, but with no spiral arms

Explanation:

A Lenticular galaxy is a kind of galaxy intermediate between elliptical galaxy and a spiral galaxy in the Morphological classification system of galaxies. They have a central bulge or disc just like a Spiral galaxy but lacks the arms of spiral galaxy. If looked edge on they appear to be spiral and if looked face on they appear to be elliptical.

The absence of spiral arms can be attributed to the absence of star formation. They mainly consists of ageing stars.

6 0
4 years ago
If the pressure exerted on a 300.0 mL sample of hydrogen gas at constant temperature is increased from 0.500 kPa to 0.750 kPa, w
uranmaximum [27]

Answer:

200 mL

Explanation:

Given that,

Initial volume, V₁ = 300 mL

Initial pressure, P₁ = 0.5 kPa

Final pressure, P₂ = 0.75 kPa

We need to find the final volume of the sample if pressure is increased at constant temperature. It is based on Boyle's law. Its mathematical form is given by :

V\propto \dfrac{1}{P}\\\\P_1V_1=P_2V_2

V₂ is the final volume

V_2=\dfrac{P_1V_1}{P_2}\\\\V_2=\dfrac{300\times 0.5}{0.75}\\\\V_2=200\ mL

So, the final volume of the sample is 200 mL.

5 0
3 years ago
The spectrum from a hydrogen vapour lamp is measured and four lines in the visible light range are observed. These lines are the
Elan Coil [88]

Answer:

10942249.24 m^{-1}

Explanation:

Rydberg's formula is used to describe the wavelengths of the spectral lines of chemical elements similar to hydrogen, that is, with only one electron being affected by the effective nuclear charge. In this formula we can find the rydberg constant, knowing the wavelength emitted in the transcision between two energy states, we can have a value of the constant.

\frac{1}{\lambda}=Z^2R(\frac{1}{n^2_{1}}-\frac{1}{n^_{2}^2}})

Where \lambda it is the wavelength of the light emitted, R is the Rydberg constant, Z is the atomic number  of the element and n_{1} n_{2} are the states where n_{1}.

In this case we have Z=1 for hydrogen, solving for R:

R=\frac{1}{\lambda}*(\frac{1}{n^2_{1}}-\frac{1}{n^_{2}^2}})^{-1}\\R=\frac{1}{658.9*10^{-9}m}*(\frac{1}{2^2}-\frac{1}{3^2}})^{-1}\\R=1.52*10^6m^{-1}*(\frac{36}{5})=1.09*10^7 m^{-1}=10942249.24m^{-1}

This value is quite close to the theoretical value of the constant R=10967758.34 m^{-1}

5 0
4 years ago
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