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galben [10]
3 years ago
10

A sled is dragged along a horizontal path at a constant speed of 1.50 m/s by a rope that is inclined at an angle of 30.0° with r

espect to the horizontal. The total weight of the sled is 470 N. The tension in the rope is 230 N. How much work is done by the rope on the sled in a time interval of 10.0 s?
Physics
1 answer:
Allisa [31]3 years ago
4 0

Answer:2987.7 J

Explanation:

Given

sled weight is W=470 N

Tension in rope T=230 N

Time interval t=10 s

velocity of sled v=1.5 m/s

here speed is equal to velocity which is constant therefore acceleration is zero

thus F_{net}=0

Distance traveled in t=10 s

x=v\times t=1.5\times 10=15 m

considering surface to be friction less

thus T\cos 30 will do work on sled

W=F\cdot x

W=T\cos 30\cdot x

W=230\cos 30\times 15

W=2987.78 J\approx 2.987 kJ

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m_a_m_a [10]

Answer:0.27

Explanation:

Given

One worker Pushes with force F_1=430 N

other Pulls it with a rope of rope F_2=360 N

mass of crate m=290 kg

both forces are horizontal and crate slides with a constant speed

Both forces are in the same direction so Friction will oppose the forces and will be equal in magnitude of sum of two forces because crate is moving with constant speed i.e. net force is zero on it

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