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Alekssandra [29.7K]
3 years ago
5

(6.0×10^4)(3.1×10^-1)

Chemistry
1 answer:
yKpoI14uk [10]3 years ago
6 0
(6.0×10^4) = 60,000
(3.1×10^-1) = 0.31

60,000 × 0.31 = 18,600
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How many centimeters are in .479 kilometers
trapecia [35]

Answer:

47900 cm

General Formulas and Concepts:

<u>Chemistry</u>

  • Base 10 Decimal System
  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

0.479 km

<u>Step 2: Identify Conversions</u>

1 km = 1000 m

1 m = 100 cm

<u>Step 3: Convert</u>

<u />0.479 \ km(\frac{1000 \ m}{1 \ km} )(\frac{100 \ cm}{1 \ m} ) = 47900. cm

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules.</em>

47900. cm ≈ 47900 cm

7 0
2 years ago
Which of the following could result from having few or no ?-1,6 linkages in glycogen? Select all that apply.
Katen [24]

Answer:

The correct answer is 1 glycogen degradation would slow down.

Explanation:

Glycogen is the principle storage polysaccharide present in the liver and muscle of human body.

    Glycogen contain both alpha-1,4-glycosidic linkage and alpha -1,6-glycosidic linkage.During glycogenolysis some glucose residues are transferred from branch point of the glycogen to its end and thereafter a single glucose residue is linked to the branch point of glycogen by alpha-1,6-glycosidic linkage.

   The alpha-1,6-glycosidic linked glucose of glycogen is finally get separated from glycogen by the catalytic activity of alpha-1,6-glycosidase enzyme in the final step of glycogenolysis.

 According to the given question if there is no alpha-1,6-glycosidic linkage in the glycogen then glycogen degradation will slow down.

     

5 0
3 years ago
What would be the correct answer please help!
bogdanovich [222]

Answer:

first number is the correct answer

6 0
3 years ago
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Ralph's friend invited him to attend a hard rock concert. Ralph did not want to go because he assumed other people who attended
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Prejudice

Explanation:

8 0
2 years ago
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A mixture of gases contains 4.46 moles of neon (Ne), 0.74 mole of argon (Ar), and 2.15 moles of xenon (Xe). Calculate the partia
viva [34]

Explanation:

The partial pressure of an individual gas is equal to the total pressure of the mixture multiplied by the mole fraction of the gas.

Total pressure = 2atm

Mole Fraction = number of moles / total number of moles

Neon

Mole Fraction = 4.46 / 7.35 = 0.607

Partial Pressure = 0.607 * 2 = 1.214 atm

Argon

Mole Fraction = 0.74 / 7.35 = 0.101

Partial Pressure = 0.101 * 2 = 0.202 atm

Xenon

Mole Fraction = 2.15 / 7.35 = 0.293

Partial Pressure = 0.293 * 2 = 0.586 atm

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3 years ago
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