Answer:
The answer to your question is below
Explanation:
Data
pOH = 5.9
a) [OH⁻] = ?
pOH measures the [OH⁻]
Formula
pOH = -log[OH⁻]
-Substitution
5.9 = -log[OH⁻]
[OH⁻] = antilog (-5.9)
-Result
[OH⁻] = 1.26 x 10⁻⁶ M
b) [H₃O⁺]
pH + pOH = 14
-Solve for pH
pH = 14 - pOH
-Substitution
pH = 14 - 5.9
-Result
pH = 8.1
-Calculate [H₃O⁺]
pH = -log[H₃O⁺]
-Substitution
8.1 = -log[H₃O⁺]
[H₃O⁺] = antilog(-8.1)
-Result
[H₃O⁺] = 7.9 x 10⁻⁹ M
c) This solution is alkaline because the pH is higher than 7.
A Nitrogen got 7 electrons, which means every Nitrogen got 3 pairs of electrons and 1 single electron, ready to be shared.
A second nitrogen come with the same amount of electrons, 3 pairs and 1 single ready to shared.
The 2 nitrogens put in common their single electrons to create a pair.
Which means, that 1 pair of electron is shared between the nitrogens in a molecule of N2
Hope this Helps! :)
I think the answer will be b cuh
There are 60 seconds in one minute
565900 / 60 = 9431.667 minutes in 565,900 seconds
There are 60 minutes in an hour
9431.667 minutes / 60 = 157.9144 hours in 565900 seconds
There are 24 hours in 1 day
157.9144 hours / 24 hours = 6.5498 days.
Answer: (E) 300 bq
Explanation:
Half life is the amount of time taken by a radioactive material to decay to half of its original value.
Radioactive decay process is a type of process in which a less stable nuclei decomposes to a stable nuclei by releasing some radiations or particles like alpha, beta particles or gamma-radiations. The radioactive decay follows first order kinetics.
Half life is represented by 
Half life of Thallium-208 = 3.053 min
Thus after 9 minutes , three half lives will be passed, after ist half life, the activity would be reduced to half of original i.e. 
, after second half life, the activity would be reduced to half of 1200 i.e. 
, and after third half life, the activity would be reduced to half of 600 i.e. 
,
Thus the activity 9 minutes later is 300 bq.
