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Crank
3 years ago
14

Write a balanced chemical equation describing the reaction of zinc and hydrochloric acid.

Chemistry
2 answers:
zhuklara [117]3 years ago
7 0

Explanation:

When zinc chemically reacts with hydrochloric acid in chemical reaction then it leads to the formation of zinc chloride along with evolution of hydrogen gas.

Chemical equation which represents this chemical reaction is as follows.

        Zn + HCl \rightarrow ZnCl_{2} + H_{2}

Number of atoms on reactant side are as follows.

Zn = 1

H = 1

Cl = 1

Number of atoms on product side are as follows.

Zn = 1

H = 2

Cl = 2

Hence, to balance this equation we will multiply HCl by 2 on reactant side. Therefore, the balanced chemical equation is as follows.

              Zn + 2HCl \rightarrow ZnCl_{2} + H_{2}

erastova [34]3 years ago
5 0
The chemical formula for zinc is Zn, and HCl for hydrogen chloride. The complete balanced equation for these reactants would be:

Zn + 2 HCl → ZnCl₂ + H₂

The stoichiometric coefficient 2 for HCl is essential to obey the Law of Conservation of Mass. The elements before and after the reaction must be equal in amounts.
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dlinn [17]

Answer: 190 g of magnesium chloride can be produced by reacting 2 moles of chlorine gas with excess magnesium bromide.

Explanation:

The balanced chemical reaction is;

Cl_2+MgBr_2\rightarrow MgCl_2+Br_2

Cl_2 is the limiting reagent as it limits the formation of product and MgBr_2 is the excess reagent.

According to stoichiometry :

1 mole of Cl_2 produces = 1 mole of MgCl_2

Thus 2 moles of Cl_2 will produce=\frac{1}{1}\times 2=2moles  of MgCl_2

 Mass of MgCl_2=moles\times {\text {Molar mass}}=2moles\times 95g/mol=190g

Thus 190 g of magnesium chloride can be produced by reacting 2 moles of chlorine gas with excess magnesium bromide

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2 years ago
Submit What is the solubility of Cd3(POA) 2 in water? (Ksp of Cd3(PO4)2 is 2.5 x 10-33) | 1 2 3 +/- . 0 x100
vesna_86 [32]

<u>Answer:</u> The solubility of Cd_3(PO_4)_2 in water is 1.18\times 10^{-7}mol/L

<u>Explanation:</u>

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The expression for solubility constant for this reaction will be:

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We are given:

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