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Crank
3 years ago
14

Write a balanced chemical equation describing the reaction of zinc and hydrochloric acid.

Chemistry
2 answers:
zhuklara [117]3 years ago
7 0

Explanation:

When zinc chemically reacts with hydrochloric acid in chemical reaction then it leads to the formation of zinc chloride along with evolution of hydrogen gas.

Chemical equation which represents this chemical reaction is as follows.

        Zn + HCl \rightarrow ZnCl_{2} + H_{2}

Number of atoms on reactant side are as follows.

Zn = 1

H = 1

Cl = 1

Number of atoms on product side are as follows.

Zn = 1

H = 2

Cl = 2

Hence, to balance this equation we will multiply HCl by 2 on reactant side. Therefore, the balanced chemical equation is as follows.

              Zn + 2HCl \rightarrow ZnCl_{2} + H_{2}

erastova [34]3 years ago
5 0
The chemical formula for zinc is Zn, and HCl for hydrogen chloride. The complete balanced equation for these reactants would be:

Zn + 2 HCl → ZnCl₂ + H₂

The stoichiometric coefficient 2 for HCl is essential to obey the Law of Conservation of Mass. The elements before and after the reaction must be equal in amounts.
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Chlorine forms a number of oxides with the following oxidation numbers: 1, 3, 4, 6, and 7. These compounds are stable and neutra
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Answer:

Cl_2O, Cl_2O_3, ClO_2, ClO_3, Cl_2O_7

Explanation:

Empirical formula of the compound is the simplest ratio of elements present in the compound.

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Compounds in which oxidation state of Cl is +1

Cl_2O

Compounds in which oxidation state of Cl is +3

Cl_2O_3

Compounds in which oxidation state of Cl is +4

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Compounds in which oxidation state of Cl is +6

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Compounds in which oxidation state of Cl is +7

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The _______ are found on the left side of the arrow in a chemical reaction.
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The reactants are found on the left side, the products are found on the right side.
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A mileage test is conducted for a new car model. Thirty randomly selected cars are driven for a month and the mileage is measure
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Answer:  (27.81,\ 29.39)

Explanation:

Given : Sample size : n= 30 , it means it is a large sample (n≥ 30), so we use z-test .

Significance level : \alpha: 1-0.95=0.05

Critical value: z_{\alpha/2}=1.96

Sample mean : \overline{x}=28.6

Standard deviation : \sigma=2.2

The formula to find the confidence interval is given by :-

\overline{x}\pm z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}

i.e. 28.6\pm (1.96)\dfrac{2.2}{\sqrt{30}}

i.e. 28.6\pm 0.787259889321

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