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4 years ago

Write a balanced chemical equation describing the reaction of zinc and hydrochloric acid.

Chemistry

2 answers:

zhuklara [117]4 years ago

7 0

Explanation:

When zinc chemically reacts with hydrochloric acid in chemical reaction then it leads to the formation of zinc chloride along with evolution of hydrogen gas.

Chemical equation which represents this chemical reaction is as follows.

$Zn + HCl \rightarrow ZnCl_{2} + H_{2}$

Number of atoms on reactant side are as follows.

Zn = 1

H = 1

Cl = 1

Number of atoms on product side are as follows.

Zn = 1

H = 2

Cl = 2

Hence, to balance this equation we will multiply HCl by 2 on reactant side. Therefore, the balanced chemical equation is as follows.

$Zn + 2HCl \rightarrow ZnCl_{2} + H_{2}$

erastova [34]4 years ago

5 0

The chemical formula for zinc is Zn, and HCl for hydrogen chloride. The complete balanced equation for these reactants would be:

Zn + 2 HCl → ZnCl₂ + H₂

The stoichiometric coefficient 2 for HCl is essential to obey the Law of Conservation of Mass. The elements before and after the reaction must be equal in amounts.

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Calculate the weight of 3.491 into 10 to the power 19 molecules of cl2

Rom4ik [11]

Answer:

The mass of 3.491 × 10¹⁹ molecules of Cl₂ of Cl₂ is 4.11 × 10⁻³ grams

Explanation:

The number of particles in one mole of a substance id=s given by the Avogadro's number which is approximately 6.023 × 10²³ particles

Therefore, we have;

One mole of Cl₂ gas, which is a compound, contains 6.023 × 10²³ individual molecules of Cl₂

3.491 × 10¹⁹ molecules of Cl₂ is equivalent to (3.491 × 10¹⁹)/(6.023 × 10²³) = 5.796 × 10⁻⁵ moles of Cl₂

The mass of one mole of Cl₂ = 70.906 g/mol

The mass of 5.796 × 10⁻⁵ moles of Cl₂ = 70.906 × 5.796 × 10^(-5) = 4.11 × 10⁻³ grams

Therefore;

The mass of 3.491 × 10¹⁹ molecules of Cl₂ of Cl₂ = 4.11 × 10⁻³ grams.

4 0

3 years ago

Consider the Van der Vaals equation of state: (????+????????????)(????−????)=???????????? where p is pressure, V is volume, n is

yanalaym [24]

Answer:

Units of a = $\frac{atm\ L^2}{mol^2}$

Units of b = $\frac{L}{mol}$

Explanation:

The Van der Waal's equation is:-

$\left(P+\frac{an^2}{V^2}\right)\left(V-nb\right)=nRT$

Where,

P is the pressure

V is the volume

n is the number of moles

T is the temperature

R is Gas constant having value

a and b are van der Waal's constant

If pressure is taken in atm and volume in L. So,

$P+\frac{an^2}{V^2}$ represents the pressure correction term. Then,

Units of a = $\frac{atm\ L^2}{mol^2}$

$V-nb$ represents the volume correction term. Then,

Units of b = $\frac{L}{mol}$

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3 years ago

Response should be in complete sentences. Answer should at least be 5-7 sentences. (Include the definition of Conservation of Ma

shusha [124]

Answer:

kkkkkkkiuouo 9o

Explanation:

8 0

2 years ago

If you mixed three Dixie cups’ contents together containing 0.05L of 1.0M lemonade, 0.05L of 2.5M lemonade, and 0.05L of 0.5M le

viva [34]

Molarity of the resulting solution will be 1.33 M.

<u>Explanation:</u>

First we have to find the number of moles for each of the solution using the formula, moles = molarity × volume

For cup 1 = 1 M ×0.05 L = 0.05 moles

For cup 2 = 2.5 M × 0.05 L= 0.125 moles

For cup 3 = 0.5 M × 0.05 L = 0.025 moles

Total moles = 0.05 + 0.125 + 0.025 = 0.2 moles

We have to find the total volume as, 0.05 + 0.05 + 0.05 = 0.15 L

Now we have to find the molarity as, moles / volume = 0.2 moles/ 0.15 L = 1.33 M

3 0

3 years ago

Doing an experiment about electroplating, you attempt to coat silver in gold using a basic electroplating set-up. You take the m

Elan Coil [88]

Answer:

it’s mass was greater than when it started

Explanation:

When a metal is coated with another metal, the plating metal deposits on the plated metal. Usually, the plating metal functions as the anode while the plated metal functions on the cathode. The anode metal is oxidized and reduced at the cathode and become deposited on the cathode material. This increases the mass of the cathode. Hence the mass of the silver/gold product is greater than the mass of silver at the beginning of the electroplating process.

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3 years ago