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Crank
4 years ago
14

Write a balanced chemical equation describing the reaction of zinc and hydrochloric acid.

Chemistry
2 answers:
zhuklara [117]4 years ago
7 0

Explanation:

When zinc chemically reacts with hydrochloric acid in chemical reaction then it leads to the formation of zinc chloride along with evolution of hydrogen gas.

Chemical equation which represents this chemical reaction is as follows.

        Zn + HCl \rightarrow ZnCl_{2} + H_{2}

Number of atoms on reactant side are as follows.

Zn = 1

H = 1

Cl = 1

Number of atoms on product side are as follows.

Zn = 1

H = 2

Cl = 2

Hence, to balance this equation we will multiply HCl by 2 on reactant side. Therefore, the balanced chemical equation is as follows.

              Zn + 2HCl \rightarrow ZnCl_{2} + H_{2}

erastova [34]4 years ago
5 0
The chemical formula for zinc is Zn, and HCl for hydrogen chloride. The complete balanced equation for these reactants would be:

Zn + 2 HCl → ZnCl₂ + H₂

The stoichiometric coefficient 2 for HCl is essential to obey the Law of Conservation of Mass. The elements before and after the reaction must be equal in amounts.
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4 years ago
Calculate the number of moles of magnesium, chlorine, and oxygen atoms in 4.90 moles of magnesium perchlorate, Mg(ClO4)2.]\
Leviafan [203]

Answer:

 4.90  moles of  Mg(ClO_4)_2   will produce  (9.8) moles of  Cl^{-} ,

                                                    (4.90) moles of Mg^{2+} and

                                                    (39.2) moles of  O^{2-}

Explanation:

From the question we are told that

  The number of moles of  is  n =  4.90  \ mols

The formation reaction of Mg(ClO_4)_2  is

             Mg^{2+} + 2 Cl^{-} + 8O^{2+} \to Mg(ClO_4)_2  

From the reaction we see that

   1 mole of  Mg(ClO_4)_2  is formed by 2 moles of Cl^{-} 1 mole of  Mg^{2+} and 4  O^{2-}

 This implies that

   4.90  moles of  Mg(ClO_4)_2   will produce  (2 * 4.90) moles of  Cl^{-} ,

                                                    (1 * 4.90) moles of Mg^{2+} and

                                                    (8 * 4.90) moles of  O^{2-}

So

  4.90  moles of  Mg(ClO_4)_2   will produce  (9.8) moles of  Cl^{-} ,

                                                    (4.90) moles of Mg^{2+} and

                                                    (39.2) moles of  O^{2-}

                           

4 0
3 years ago
Read 2 more answers
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