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3 years ago

I will give brainliest to the best answer.

Mathematics

1 answer:

aniked [119]3 years ago

7 0

Given that two digit numbers are used and one digit is drawn randomly.

Sample space = {10,11,...99}

n(S) = 90

32 is only one number favorable

Hence P(32) = 1/90

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Odd numbers are exactly 45.

Hence prob (odd number) = 45/90 = 1/2

-------------------------------------

Multiples of 5 are 10,15,.....95

There are exactly 18 numbers.

Hence P(a multiple of 5) = 18/90 =1/5

Have an amazing day! <3

You might be interested in

Find the unknown of the following

abruzzese [7]

Step-by-step explanation:

For 4.

4b + 2b + 3b = 180°< Sum of angles of triangle >

9b = 180°

b = 180° / 9

b = 20°

4b = 4* 20° = 80°

2b = 2* 20° = 40°

3b = 3 * 20° = 60°

For 5.

x = 64° + 45° <Exterior angle of a triangle is equal to the sum of two opposite interior angles>

x = 109°

Hope it helps :)

8 0

3 years ago

A manufacturer reported a sample mean = 22.0 g and a sample standard deviation = 2.5 g based on a sample of 20 of their products

tester [92]

Answer:

$n=(\frac{1.640(2.5)}{2})^2 =4.2 \approx 5$

So the answer for this case would be n=5 rounded up to the nearest integer

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=22$ represent the sample mean

$\mu$ population mean (variable of interest)

s=2.5 represent the sample standard deviation

n represent the sample size

ME = 2 represent the margin of error accepted

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (2)

And on this case we have that ME =2 and we are interested in order to find the value of n, if we solve n from equation (2) we got:

$n=(\frac{z_{\alpha/2} s}{ME})^2$ (3)

We can use as estimator for the population deviation the sample deviation $\hat \sigma = s$

The critical value for 90% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.05;0;1)", and we got $z_{\alpha/2}=1.640$ , replacing into formula (3) we got: