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miskamm [114]
2 years ago
6

Pls help me with this!

Mathematics
1 answer:
goldfiish [28.3K]2 years ago
5 0

Answer:

1)B

2) Acute angle

3) KJL        LJK     i don't know the last one

Step-by-step explanation:

You might be interested in
Determine whether the statement is always true, sometimes true, or never true. Give an example. (a) Both sides of an equation ca
arsen [322]

Answer:

(A) Always true

(B) Seldom true

Step-by-step explanation:

(A) Both sides of an equation can be multiplied by the same number without this action changing the solution of the equation.

Keyword here is "number".

Multiplying both sides of an equation by an equal quantity (same number) will result in same solution after solving for the unknown in the equation. This is because that numeric quantity can always be removed by dividing both sides of the equation by it or by a factor (or multiple) of it.

EXAMPLE:

For a linear equation, 4x - 6 = 15x

let's find the solution, in other words solve for the unknown value X.

4x - 15x = 6

-11x = 6

x = -6/11

Now multiply both sides of the equation by 3.

3(4x - 6) = 3(15x)

12x - 18 = 45x   ___new equation

Solve for X

12x - 45x = 18

-33x = 18

x = -18/33

Reduce the fraction to its simplest form by looking for a number that can divide both numerator and denominator without remainder. In other words, think of a number that is a factor of 18 and a factor of 33.

That common factor or highest common factor (HCF) is 3.

Go ahead and reduce the fraction.

x will be reduced to -6/11

(B) Both sides of an inequality can seldom be multiplied by the same number, without such action changing the solution set of the equation.

Inequalities are more complex. Operational signs even change sometimes, in the course of finding the solution set of the inequality.

Sometimes, multiplying both sides of an inequality by a given numeric quantity will change its solution set and sometimes, it won't.

5 0
3 years ago
Solve the equation by completing the square
Nana76 [90]

Answer:

s = - 1 ± \sqrt{7}

Step-by-step explanation:

Given

s² + 2s - 6 = 0 ( add 6 to both sides )

s² + 2s = 6

To complete the square

add ( half the coefficient of the s- term )² to both sides

s² + 2(1)s + 1 = 6 + 1

(s + 1)² = 7 ( take the square root of both sides )

s + 1 = ± \sqrt{7} ( subtract 1 from both sides )

s = - 1 ± \sqrt{7}

Thus

s = - 1 - \sqrt{7} , s = - 1 + \sqrt{7}

4 0
3 years ago
How do you write negative 4 tenths as a fraction?
jasenka [17]

Answer:

-4/10

Step-by-step explanation:

6 0
3 years ago
3/4 = x/20 i need the answer i beg
Nady [450]

Answer:

15/20

Step-by-step explanation:

4 x 5 = 20

so

3 x 5 = 15

so (sorry for the repetition)

= 15/20

8 0
2 years ago
This question is like impossible idk
7nadin3 [17]
If the problem was written x + 4x.  We would know to add like the coefficients together and get 5x  same thing with the radicals.

\sqrt{3} + 4 \sqrt{3} = 5 \sqrt{3}
3 0
3 years ago
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