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3 years ago

WILL UPVOTE EVERY ANSWER! MULTIPLE CHOICE QUESTION!

1 answer:

5 0

The answer is: [<span>B]:
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the elastic constant, a number that tells the relative strength of the spring .
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WILL AWARD BRAINLIEST! How many moles of iron (III) oxide are produced when 0.275 moles of iron is reacted?

aev [14]

Answer:

Arrow should be yeilds, THE COEFFICIENTS are mole ratios. So every 4 moles of NH3 or ammonia produce 6 moles of H2O water

8 0

3 years ago

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For the reaction below, Kp = 1.59 at 100°C. If 1.0 g of SrCO3 is placed in an empty 5.00 L reactor and allowed to reach equilibr

Sergio [31]

Answer:

$p_{CO_2}^{eq}=1.59atm$

Explanation:

Hello, in this case, one could consider the undergoing chemical reaction as:

$SrCO_3(s)\rightleftharpoons SrO(s)+CO_2(g)$

Thus, since 1.0 g of strontium carbonate is placed, the equilibrium equation takes the following form, excluding the solid-stated species and considering just the carbon dioxide as it is gaseous:

$Kp=p_{CO_2}^{eq}=1.59atm$

Hence, since at the beginning there is no carbon dioxide, its pressure at equilibrium equals Kp:

$Kp=p_{CO_2}^{eq}=1.59atm$

Which was clearly defined above.

Best regards.

8 0

3 years ago

If acetic acid is the only acid that vinegar contains (ka=1.8×10−5), calculate the concentration of acetic acid in the vinegar.

kicyunya [14]

Ethanoic (Acetic) acid is a weak acid and do not dissociate fully. Therefore its equilibrium state has to be considered here.

$CH_{3}COOH \ \textless \ ---\ \textgreater \ H^{+} + CH_{3}COO^{-}$

In this case pH value of the solution is necessary to calculate the concentration but it's not given here so pH = 2.88 (looked it up)

pH = 2.88 ==> $[H^{+}]$ = $10^{-2.88}$ = 0.001 $moldm^{-3}$

The change in Concentration Δ $[CH_{3}COOH]$ = 0.001 $moldm^{-3}$

  CH3COOH H+ CH3COOH
Initial   $moldm^{-3}$      $x$ 0 0

Change $moldm^{-3}$ -0.001 +0.001 +0.001

Equilibrium $moldm^{-3}$ $x$ - 0.001 0.001 0.001


Since the $k_{a}$ value is so small, the assumption
$[CH_{3}COOH]_{initial} = [CH_{3}COOH]_{equilibrium}$ can be made.

$k_{a} = [tex]= 1.8*10^{-5} = \frac{[H^{+}][CH_{3}COO^{-}]}{[CH_{3}COOH]} = \frac{0.001^{2}}{x}$

Solve for x to get the required concentration.

note: 1.)Since you need the answer in 2SF don&t round up values in the middle of the calculation like I've done here.

2.) The ICE (Initial, Change, Equilibrium) table may come in handy if you are new to problems of this kind

Hope this helps!

8 0

3 years ago

for the reaction shown compute the theoretical yield of product in moles each of the initial quantities of reactants. 2 Mn(s)+3

Y_Kistochka [10]

Answer:

2 mole MnO₂

Explanation:

2Mn(s) + 2O₂(g) => 2MnO₂(s)

4 0

4 years ago

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Consider the following element combinations. Classify the bonds formed between each pair as ionic, polar covalent, or nonpolar c

Sati [7]

An ionic bond is formed by the transfer of electrons from one atom to the other. It is usually formed between a metal + non-metal.

A covalent bond is formed by sharing of electrons between two atoms. It is formed between two nonmetals. A polar covalent bond is formed between 2 non-metals which differ in their electronegativities. In contrast, in a non-polar covalent interaction the two atoms could either be the same or have very close electronegativities.

1) P and I : Both non-metals with different electronegativities= Polar Covalent

2) Fe and O: Metal + non-metal = Ionic

3) S and Cl: Both non-metals with different electronegativities= Polar Covalent

4) S and S: Both non-metals and the same atoms = Non-polar Covalent

5) Br and Br: Both non-metals and the same atoms = Non-polar Covalent

6) O and Cl: Both non-metals with different electronegativities= Polar Covalent

7) Be and Cl: Metal + non-metal = Ionic

8) Al and N: Metal + non-metal = Ionic

5 0

3 years ago

Read 2 more answers