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Alchen [17]
3 years ago
11

The positive acute angle formed by the _____ side of an angle in standard position and the x-axis is called a reference angle.

Mathematics
1 answer:
Helga [31]3 years ago
7 0

Answer:

option-C

terminal

Step-by-step explanation:

We know that

reference angle is between terminal side and x-axis

so, the other side will be terminal position

so, we can write as

The positive acute angle formed by the <u>terminal</u> side of an angle in standard position and the x-axis is called a reference angle.

So,

option-C

terminal

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Pls help I don’t understand
dmitriy555 [2]

The answer is c. \frac{46}{9}

a. \frac{11}{5}=2.2 (2.2≠5.11) (2.2 is not equal to 5.11)

b. 5\frac{1}{8}=\frac{5}{8} or 0.625 (0.625≠5.11) (0.625 is not equal to 5.11)

c. \frac{46}{9} =5.11 (5.11=5.11) (5.11 is equal to 5.11)

Therefore c is the answer

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3 years ago
What is the solution to this equation x-16=-8
arsen [322]
X-16=-8
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3 years ago
Which expression is equivalent to x y Superscript two-ninths?
crimeas [40]

Option D: x\sqrt[9]{y^2} is the expression equivalent to xy^{\frac{2}{9}}

Explanation:

Option A: \sqrt{xy^9}

The expression can be written as ({xy^9})^{\frac{1}{2}

Applying exponent rule, we get,

x^{\frac{1}{2}} y^{\frac{9}{2}}

Thus, the expression \sqrt{xy^9} is not equivalent to the expression xy^{\frac{2}{9}}

Hence, Option A is not the correct answer.

Option B: \sqrt[9]{xy^2}

The expression can be written as ({xy^2})^{\frac{1}{9}

Applying exponent rule, we get,

x^{\frac{1}{9}} y^{\frac{2}{9}}

Thus, the expression \sqrt[9]{xy^2} is not equivalent to the expression xy^{\frac{2}{9}}

Hence, Option B is not the correct answer.

Option C: x\sqrt{y^9}

The expression can be written as x(y^9)^{\frac{1}{2} }

Applying exponent rule, we get,

x y^{\frac{9}{2}}

Thus, the expression x\sqrt{y^9} is not equivalent to the expression xy^{\frac{2}{9}}

Hence, Option C is not the correct answer.

Option D: x\sqrt[9]{y^{2} }

The expression can be written as x(y^2)^{\frac{1}{9} }

Applying exponent rule, we get,

xy^{\frac{2}{9}}

Thus, the expression xy^{\frac{2}{9}} is equivalent to the expression xy^{\frac{2}{9}}

Hence, Option D is the correct answer.

4 0
3 years ago
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A student is working on a project for which he records the revolutions per minute (rpm) for a small electric motor as he increas
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Answer:

See below ↓

Step-by-step explanation:

The relation is :

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<u>Title</u> : Variation of Motor Speed with Applied Voltage

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As it constantly varies with a value of x and they are not isolated data points, they should be connected with a line.

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