Well because it has momentum and it needs to be slowed down.
The frequency of the wave is determined as 7.96 Hz.
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Frequency of the wave</h3>
The frequency of the wave is calculated as follows;
y = A sin(ωt - kx)
where;
- A is amplitude of the wave
- ω is angular speed of the wave
ω = 2πf
f = ω/2π
f = (50)/(2π)
f = 7.96 Hz
Thus, the frequency of the wave is determined as 7.96 Hz.
Learn more about frequency of waves here: brainly.com/question/6297363
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Let's write the equations of motion on both x- (horizontal) and y- (vertical) axis. On the x-axis, it's a uniform motion with constant velocity vx. On the y-axis, it is a uniformly accelerated motion with initial height h=90 m and acceleration of

pointing down (so with a negative sign):


First, let's find the time at which the jumper reaches the ground. This happens when Sy(t)=0:

and so

Then, we can find the horizontal speed. In fact, we know that at the time t=4.28 s, when the jumper reached the ground, he covered exactly 180 m, so Sx=180 m. Using this into the law of motion in x, we find
Answer:
acceleration is the vector quantity because it depends on particular direction and has magnitude