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2 years ago

Limestone formations in caves are considered what kind of weathering?

Physics

1 answer:

Zanzabum2 years ago

8 0

Answer:

Explanation:

because the carbonic acid reacts to the limestone.

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A block moves up a 30 degree incline under the action of three applied forces. F1 is horizontal and of magnitude 40 N. F2 is nor

Alja [10]

Answer

given,

F₁ is horizontal = 40 N

F₂ is normal = 20 N

F₃ is parallel = 30 N

work done by

W₂ = 0 as force is acting perpendicular to the direction of motion.

as the motion moved to 0.8 cm

W₃ = F₃ x d

W₃ = 30 x 0.8

W₃ = 24 J

W₁ = F₁ x d

W₁ = F₁ cos ∅ x d

W₁ = 40 cos 30⁰ x 0.8

W₁ = 27.21 J

4 0

4 years ago

Frank’s automobile engine runs at 100∘C. One day, when the outside temperature is 15∘C, he turns off the ignition and notes that

lapo4ka [179]

Answer:

the engine cool to 40 $^{o}C$ at 14.07 minutes

Explanation:

Given information

T(5) = 70 $^{o}C$

$T_{0}$ = 100 $^{o}C$

C = 15 $^{o}C$

Newton's law of cooling :

T(t) = C + ( $T_{0}$ - C) $e^{-kt}$

where

T(t) = temperature at any given time

C = surrounding temperature

$T_{0}$ = initial temperature of heated object

k = cooling constant

to find the the time when the engine will be cooled down to 40 $^{o}C$ , we first need to find the cooling constant, k

when t = 5, T(5) = 70 $^{o}C$

so,

T(t) = C + ( $T_{0}$ - C) $e^{-kt}$

T(5) = 15 + (100 - 15) $e^{-5k}$

70 = 15 + (85) $e^{-5k}$

$e^{-5k}$ = (70 - 15) / 85

-5k = ln (55/85)

k = - ln (55/85) / 5

k = 0.087

thus, we have the eqaution

T(t) = 15 + (85) $e^{-0.087t}$

now we can determine the time when T(t) = 40 $^{o}C$

40 = 15 + (85) $e^{-0.087t}$

$e^{-0.087t}$ = (40-15)/85

-0.0087t = ln (25/85)

t = - ln (25/85)/0.087

t = 14.07 minutes

8 0

3 years ago

20 POINTS

bekas [8.4K]

They can pretty much be by water i think

5 0

3 years ago

Two bodies A and B with 8 Kg and 24 kg respectively move

Contact [7]

It’s a speed of 15 m/s so it would be their velocities after collision

6 0

3 years ago

A block with a volume of 12cm has a density of 3cm. The block is cut into two pieces. One piece has a volume of 8cm, and the oth

professor190 [17]

Answer:

Density does not change when you divide the cube, due to the principle of mass conservation. The density given in this case by 3 $\frac{g}{cm^{3}}$ , will remain the same.

The only way for it to change, will be if you compressed the block, so now the same mass will be compressed in less volume, or you add heat to the system.

Explanation:

3 0

3 years ago