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andrezito [222]
3 years ago
5

Two bar magnets are labeled A and B. The ends of each magnet are numbered 1 or 2, but the poles are not labeled. When A1 is brou

ght near B1, the bars repel.
Which conclusion is best supported by the data?

A) A1 is the north pole of a magnet, and B1 is the south pole of a magnet.
B) A1 is the north pole of a magnet, and B1 is the north pole of a magnet.
C) A1 and B1 are opposite poles, but there is not enough information to tell which ones.
D) A1 and B1 are like poles, but there is not enough information to tell whether they are north poles or south poles.
Physics
2 answers:
olga2289 [7]3 years ago
3 0

The conclusion that is best supported by the data is;

D) A1 and B1 are like poles, but there is not enough information to tell whether they are north poles or south poles.

Anarel [89]3 years ago
3 0

Answer:

D) A1 and B1 are like poles, but there is not enough information to tell whether they are north poles or south poles.

Explanation:

When A1 is brought near B1 the bars will repel each other

As we know by the properties of magnet that when two bars are of similar nature then they will repel each other

so here A1 and B1 are of same type

so correct option must be

D) A1 and B1 are like poles, but there is not enough information to tell whether they are north poles or south poles.

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Explanation:

Given

Plane wishes to fly in west

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Plane absolute speed=195 km/h

To fly towards west velocity in Y direction should be zero

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\theta =9.96^{\circ}

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3 years ago
Scientists use what scale to compare the hardness of minerals?
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4 0
2 years ago
A cylinder with a moving piston expands from an initial volume of 0.250 L against an external pressure of 2.00 atm. The expansio
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The final volume of the gas is 144.25 L

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For the gas in the cylinder in this problem,

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A proton moving at 3.0 × 10^4 m/s is projected at an angle of 30° above a horizontal plane. If an electric field of 400 N/C is a
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Answer:

The time it takes the proton to return to the horizontal plane is 7.83 X10⁻⁷ s

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From Newton's second law, F = mg and also from coulomb's law F= Eq

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T = (2usinθ/g) ---------equation 2

Substitute in the value of g into equation 2

T = \frac{2usin \theta}{\frac{Eq}{m}} =\frac{m* 2usin \theta}{Eq}

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How force is useful

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