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Hi Pupil Here's Your answer ::
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No, on a circle in going from one point around circular path the displacement is zero but the distance covered is equal to the circumference of the circle.
i.e.
⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅
Hope this helps . . . . . . .
Answer:
1. T₁ = 500 N
2. T₂ = 866 N
Explanation:
Please see attached photo for the diagram.
Thus, we can obtain obtained the value of T₁ and T₂ as follow:
1. Determination of T₁
Angle θ = 30
Hypothenus = 100 kg
Opposite = T₁ =?
Sine θ = Opposite /Hypothenus
Sine 30 = T₁ / 100
Cross multiply
T₁ = 100 × Sine 30
T₁ = 100 × 0.5
T₁ = 50 Kg
Multiply by 10 to express in Newton
T₁ = 50 × 10
T₁ = 500 N
2. Determination of T₂
Angle θ = 60
Hypothenus = 100 kg
Opposite = T₂ = ?
Sine θ = Opposite /Hypothenus
Sine 60 = T₂ / 100
Cross multiply
T₂ = 100 × Sine 60
T₂ = 100 × 0.8660
T₂ = 86.6 Kg
Multiply by 10 to express in Newton
T₂ = 86.6 × 10
T₂ = 866 N
