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tankabanditka [31]
3 years ago
6

I NEED AN ANSWER ASAP!!!!!!!!!!!! PLEASE HELP ME!!!!!!!!!!!!!!! A 1.5m wire carries a 9 A current when a potential difference of

58 V is applied. What is the resistance of the wire?
Answer:               Units:


I need both please
Physics
1 answer:
erik [133]3 years ago
4 0

           Resistance  =  (voltage) / (current)

                               =   (58 v)  /  (9 A)

                               =        6.44 ohms

(The number would not be an answer without units.)
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Answer:

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A wire carrying a current of 26.9 A is bent into a circular arc with a radius of 0.6 cm that sweeps out 0.900 radians. What is t
melomori [17]

The magnetic field at the center of the arc is 4 × 10^(-4) T.

To find the answer, we need to know about the magnetic field due to a circular arc.

<h3>What's the mathematical expression of magnetic field at the center of a circular arc?</h3>
  • According to Biot savert's law, magnetic field at the center of a circular arc is
  • B=(μ₀ I/4π)× (arc/radius²)
  • As arc is given as angle × radius, so

        B=( μ₀I/4π)×(angle/radius)

<h3>What will be the magnetic field at the center of a circular arc, if the arc has current 26.9 A, radius 0.6 cm and angle 0.9 radian?</h3>

B=(μ₀ I/4π)× (0.9/0.006)

  = (10^(-7)× 26.9)× (0.9/0.006)

  = 4 × 10^(-4) T

Thus, we can conclude that the magnitude of magnetic field at the center of the circular arc is 4 × 10^(-4) T.

Learn more about the magnetic field of a circular arc here:

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5 0
2 years ago
A woman is applying 300N/m2 of pressure on to door with her hand. Her hand has area of 0.02m2. Work out the force being applied​
never [62]

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6N

Explanation:

Given parameters:

Pressure applied by the woman  = 300N/m²

Area = 0.02m²

Unknown:

Force applied  = ?

Solution:

Pressure is the force per unit area on a body

        Pressure  = \frac{force}{area}

         Force  = Pressure x area

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8 0
3 years ago
A lead nucleus is spherical with a radius of about 7 ✕ 10⁻¹⁵ m. The nucleus contains 82 protons (and typically 126 neutrons). Be
Komok [63]

Answer:

∈=3.1584x10^{26} \frac{V}{m}

Explanation:

Using the Gauss Law to determine the electric field of the net flux at the surface of the nucleus

∈=\frac{P}{E_{o}}

The P is the charge density and 'Eo' is the constant of permittivity in free space

to find P

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∈=3.1584x10^{26} \frac{V}{m}

3 0
3 years ago
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