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Serggg [28]
3 years ago
9

Find the perimeter of the rectangle if each block represents one foot(show your calculation)

Physics
1 answer:
iren2701 [21]3 years ago
4 0

I'm pretty sure that the "block" of which you speak is one in a pattern
of them that covers the drawing you have of the rectangle, and now
I need to explain something to you: 

The REASON for printing that drawing next to the question that you
partially copied is that the drawing has information that's needed to
answer the question with, and rather than repeat all that information
in the question, it just says "LOOK AT THE DRAWING !"

In fact, the whole point of the question may not be just to remind you of
what "perimeter" means.  It's more likely that the purpose of this problem
is to make you pick the information you need off of a drawing. 

Either way, if you'll kind of "read between the lines" of the part of the
question that you DID copy, it should be pretty obvious to you that nobody's
going nowhere in the direction of a solution without SEEing the drawing. 

So my bottom-line conclusion regarding a solution for this problem is: 
Not possible with the given information.

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calculate the gravitational force in between two objects of mass 25 kg and 20 kg if distance between them is 5m ​
sladkih [1.3K]

Answer:

<em><u>Gravitational</u></em><em><u> </u></em><em><u>force</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>1</u></em><em><u>.</u></em><em><u>3</u></em><em><u>3</u></em><em><u> </u></em><em><u>×</u></em><em><u> </u></em><em><u>1</u></em><em><u>0</u></em><em><u>^</u></em><em><u>-</u></em><em><u>9</u></em><em><u> </u></em><em><u>N</u></em>

Explanation:

force =  \frac{GMm}{ {r}^{2} }

{ \sf{ =  \frac{6.67 \times  {10}^{ - 11} \times 25 \times 20 }{ {5}^{2} } }} \\  \\  = { \sf{1.33 \times  {10}^{ - 9} \: newtons }}

5 0
3 years ago
Can someone please give me a testable question for Oxygen. I cant think of one for the life of me.
alexandr1967 [171]

Answer:

Explanation:

You could test effect of oxygen levels on growth of a regular houseplant. You could make the control to be plant grown under regular atmospheric Oxygen level. And for changing variables you could have one plant grow at low oxygen level compared to atmospheric oxygen and another plant to grow at higher levels of oxygen when compared to atmospheric oxygen.

3 0
3 years ago
The Hertzsprung-Russel diagram is used to show the relationship between which two characteristics of stars?
kykrilka [37]
Between the stars' absolute magnitudes<span> or </span>luminosities<span> versus their </span>stellar classifications<span> or </span>effective temperatures<span>. </span>
7 0
3 years ago
Read 2 more answers
Two resistors have resistances R1 and R2. When the resistors are connected in series to a 12.7-V battery, the current from the b
OLEGan [10]

Answer:

5.065 Ohm,  1.935 Ohm

Explanation:

when the resistors are connected in series.

Rs = R1 + R2

by using Ohm's law

V  = I Rs

12.7 = 1.81 x Rs

So, R1 + R2 = 7 Ohm      ...... (1)

When the resistors are connected in parallel.

Rp = R1 x R2 / (R1 + R2)

Using Ohm's law

V = I Rp

12.7 = 9.06 x Rp

R1 x R2 / (R1 + R2) = 1.4 ohm

Substitute the value of R1 + R2 from equation (1)

R1 x R2 = 1.4 x 7

R1 x R2 = 9.8

R1 - R2 = \sqrt{(R1 + R2)^{2}-4R1\times R2}

R1 - R2 = \sqrt{(49-39.2)}

R1 - R2 = 3.13 Ohm    ......(2)

By solving equation (1) and equation (), we get

R1 = 5.065 Ohm

R2 = 1.935 Ohm

5 0
3 years ago
Airplane A , starting from rest with constant acceleration, requires a runway 400 m long to become airborne. Airplane B requires
MatroZZZ [7]

Questions

1. How long must the runway be for airplane B

2.If airplane A takes time T to travel the length of its runway, how long (in terms of T) will airplane B take to travel the length of its runway?

Explanation:

Constant acceleration question

Airplane A start from rest

Then, the initial velocity is u=0m/s.

The runaway before is flight is 400m.

Time A use to travel is T

Therefore, t1=T

For plane B

Airplane B starts from rest too

i.e u=0m/s.

Let the distance Plane B covers be L.

Let the time plane B use to travel be t

Given that they both have the same acceleration

Then,

The final speed of airplane B is twice that of plane A.

Let the final speed of plane A =x

Then, final speed of plane B = 2x.

Using equation of motion

V=u+at

V^2=U^2+2as

S=ut+1/2at^2

For plane A

V=u+at; x=0+aT,

since T is time plane A use to travel

x=aT

For plane B

V=u+at; 2x=0+at

Since t is the time plane B use

2x=at Equation 2

Then, substituting x into equation 2

2(aT)=at

Then

2aT=at.

Divide both side by a, since the both have the same acceleration

2T=t

Also using

V^2=U^2+2as

Plane A.

(x)^2=0^2+2(a)(400)

x^2=800a

Plane B

(2x)^2=0^2+2(a)(L)

4x^2=2aL

divide both side by 2

2x^2=aL

Now substituting x^2=800a

2(800a)=aL

1600a=aL

Since they both have the same acceleration, divide both side by a

Then,

L=1600m

1. The runway distance the plane B will cover is 1600m

2. And the time B will cover the runway in terms of time(T) A covers is run way.

t=2T

i.e twice the time plane A will cover it owns distance

7 0
4 years ago
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