Answer:
The mass of the ice block is equal to 70.15 kg
Explanation:
The data for this exercise are as follows:
F=90 N
insignificant friction force
x=13 m
t=4.5 s
m=?
applying the equation of rectilinear motion we have:
x = xo + vot + at^2/2
where xo = initial distance =0
vo=initial velocity = 0
a is the acceleration
therefore the equation is:
x = at^2/2
Clearing a:
a=2x/t^2=(2x13)/(4.5^2)=1.283 m/s^2
we use Newton's second law to calculate the mass of the ice block:
F=ma
m=F/a = 90/1.283=70.15 kg
Answer:
Explanation:
Same numbers of protons but different number of neutron so i would go for A same atomic number different number of neutrons
Answer:
Explanation: heat of fusion
Answer:
258774.9441 m
Explanation:
x = Distance of probe from Earth
y = Distance of probe from Sun
Distance between Earth and Sun = 
G = Gravitational constant
= Mass of Sun = 
= Mass of Earth = 
According to the question
The probe should be 258774.9441 m from Earth
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