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Gemiola [76]
3 years ago
15

Which of the following is not an ethical consideration of social research?

Physics
2 answers:
laiz [17]3 years ago
4 0
I belive it it is C, using research to reform society
Stolb23 [73]3 years ago
3 0

Answer: Option (c) is the correct answer.

Explanation:

A research followed by a systematic plan and conducted by social scientists is known as social research.

In this research, scientists tend to learn about the society and people of the society in order to develop products and services to fulfill the needs of people.

Hence, we can conclude that using research to reform society is not an ethical consideration of social research.


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A speaker vibrates at a frequency of 200 hz what is its period
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Period = (1) / (frequency)

Period = (1) / (200 per second)  =  0.005 second  =  5 milliseconds

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2 years ago
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Your answer is C) The speed of sound is higher in solids than in liquids. 
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Is a Joule the same as a Kelvin?
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No,because a Kevin is 7.242971666663E+22 times Smaller than a Joule.
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Determine the velocity that a car should have while traveling around a frictionless curve of radius 100m and that is banked 20 d
alex41 [277]

Answer:

v=18.89\frac{m}{s}

Explanation:

From the free-body diagram for the car, we have that the normal force has a vertical component and a horizontal component, and this component act as the centripetal force on the car:

\sum F_x:Nsin(20^\circ)=ma_c(1)\\\sum F_y:Ncos(20^\circ)=mg(2)

Solving N from (2) and replacing in (1):

N=\frac{mg}{cos(20^\circ)}\\(\frac{mg}{cos(20^\circ)})sin(20^\circ)=ma_c\\gtan(20^\circ)=a_c

The centripetal acceleration is given by:

a_c=\frac{v^2}{r}

Replacing and solving for v:

gtan(20^\circ)=\frac{v^2}{r}\\v=\sqrt{grtan(20^\circ)}\\v=\sqrt{9.8\frac{m}{s^2}(100m)tan(20^\circ)}\\v=18.89\frac{m}{s}

4 0
3 years ago
The voltage ???? in a simple electrical circuit is slowly decreasing as the battery wears out. The resistance ???? is slowly inc
zimovet [89]

Answer:

The change in current at  R =456 \Omega is  \frac{dI}{dt}  = 7.032 * 10^{-5} A/s

Explanation:

From the question we are told that

    The resistance is R = 465 \Omega

     The current is  I = 0.09A

    The change in voltage with respect to time is \frac{dV}{dt}  = - 0.03 V/s

     The change in resistance with time is  \frac{dR}{dt}  =  0.03 \Omega /s

According to ohm's law

        V =  IR

differentiating with respect to time using chain rule

             \frac{dV}{dt}  =  I \frac{dR}{dt} + R * \frac{dI}{dt}

substituting value  at R = 456

             -0.0327 =  0.09 * 0.03 + 456* \frac{dI}{dt}

              \frac{dI}{dt}  = 7.032 * 10^{-5} A/s

6 0
2 years ago
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