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BartSMP [9]
3 years ago
8

Explain how you can use boyle's law to determine the new volume of gas when its pressure is increased from 270 kPa to 540 kPa? T

he original volume of gas was 1 L. Assume the temperature and number of particles are constant. What is the new volume?
Chemistry
1 answer:
LUCKY_DIMON [66]3 years ago
7 0
There are several information's already given in the question. Based on the information's the answer can be easily deduced. 

We know the formula

<span>P1*V1/T1 = P2*V2/T2
</span>
As the temperature is constant, so T1 and T2 can be negated. The formula changes to 
<span>P1*V1 = P2*V2
</span>70 * 1 = 540 * V2
270/540 = V2
<span>V2 = 0.5
</span>
From the above deduction, we can conclude that the new volume is 0.5 liters. I hope that the procedure is clear enough for you to understand.
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A rigid tank that contains 2 kg of N2 at 25°C and 550 kPa is connected to another rigid tank that contains 4 kg of O2 at 25°C an
koban [17]

Answer:

The volume in the first tank = 0.32 m^{3}

The volume in the second tank = 2.066 m^{3}

The  final pressure of the mixture = 203.64 K pa

Explanation:

<u>First Tank </u>

Mass = 2 kg

Pressure = 550 k pa

Temperature = 25 °c = 298 K

Gas constant for nitrogen = 0.297 \frac{KJ}{Kg K}

From the ideal gas equation

P V = m R T

550 × V = 2 × 0.297 × 298

V = 0.32 m^{3}

This is the volume in the first tank.

<u>Second tank</u>

Mass =  4 kg

Pressure = 150 K pa

Temperature = 25 °c = 298 K

Gas constant for oxygen = 0.26  \frac{KJ}{Kg K}

From the ideal gas equation

P V = m R T

150 × V = 4 × 0.26 × 298

V = 2.066 m^{3}

This is the volume in the second tank.

This is the iso thermal mixing. i.e.

P_{3} V_{3}  = P_{1} V_{1} + P_{2} V_{2} ----- (1)

V_{3}  = V_{1}  + V_{2}

V_{3}  = 0.32 + 2.066

V_{3}  = 2.386 \ m^{3}

Put this value in equation (1)

P_{3} × 2.386 =  550 × 0.32 + 150 × 2.066

P_{3} = 203.64 K pa

Therefore the  final pressure of the mixture = 203.64 K pa

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3 years ago
Are alcohols with more than one hydroxyl group attached to a carbon sequence.
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Answer:

Polyhydroxyl alcohols

Explanation:

Whenever we have several C-OH bonds, we have a polyhydroxyl alcohol. For example, if we have just one alcohol group, that is, an R-OH group, then the naming is simple, say, we have EtOH, it's ethanol.

The problem becomes more complicated when we have several hydroxyl groups present in the alcohol. Let's say we have an ethane molecule and we replace the hydrogen atoms of carbon 1 and 2 with hydroxyl groups. In that case, we have 1,2-ethanediol. Similarly, we can have triols etc.

That said, we have poly (several) hydroxyl groups and we can generalize this to having polyhydroxyl alcohols.

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Answer:

Research shows that patients with schizophrenia are more affected by stress physically as well as emotionally, for instance they show different changes in heart rate under stress and a greater overall risk of cardiovascular disease.

Explanation:

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A gas is contained in a cylinder with a volume of 2.9 L at a temperature of 32.7oC and a pressure of 645.3 torr. The gas is then
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Answer: 41 atm

Explanation:

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Original Volume of gas V1 = 2.9L

Temperature T1 = 32.7°C

Convert Celsius to Kelvin

(32.7°C + 273 = 305.7K)

Pressure P1 = 645.3 torr

New Volume V2 = 0.23 L

New temperature T2 = 894.7°C

Convert Celsius to Kelvin

(894.7°C + 273 = 1167.7K)

New pressure = ?

Then, apply the combined gas equation

(P1V1)/T1 = (P2V2)/T2

(645.3 torr x 2.9L)/305.7K = (P2 x 0.23L)/1167.7K

1871.37 / 305.7 = 0.23P2 / 1167.7

To get P2, Cross multiply

1871.37 x 1167.7 = 305.7 x 0.23P2

2185198.749 = 70.311P2

Divide both sides by 70.311

2185198.749/70.311 = 70.311P2/70.311

31079.045 torr = P2

Now, convert pressure in torr to atmosphere

Since 760 torr = 1 atm

31079.045 torr = Z

cross multiply

760 torr x Z = 31079.045 torr x 1 atm

Z = 31079.045 torr / 760 torr

Z = 40.89 atm (Round to the nearest whole number as 41 atm)

Thus, new pressure of gas is 41 atm

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Answer:

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Explanation:

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