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Arte-miy333 [17]
2 years ago
13

What volume will 2.50 mol of hydrogen (H2) occupy at -20.0 °C and 1.5 atm?

Chemistry
1 answer:
svet-max [94.6K]2 years ago
5 0

Answer:

v = 34.62 L

Explanation:

Given data:

Moles of H₂ = 2.50 mol

Temperature of gas = -20.0°C

Pressure of gas = 1.5 atm

Volume of gas = ?

Solution:

Formula:

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

Now we will convert the temperature.

-20 + 273 = 253 K

Now we will put the values in formula.

1.5 atm × v = 2.50 mol ×0.0821 atm.L/ mol.K  ×  253 K

1.5 atm × v = 51.93 atm.L

v = 51.93 atm.L/1.5 atm

v = 34.62 L

The volume of hydrogen is 34.62 L.

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5 0
3 years ago
A 34.0 g piece of metal is heated to 92.0°C then placed in a beaker of water containing 22.0 g of water at 19.0°C. The temperatu
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Answer:

0.1988 J/g°C

Explanation:

-Qmetal = Qwater

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c = specific heat of substance

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Hence;

-{mc∆T} of metal = {mc∆T} of water

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For metal; m= 34.0g, ∆T = (24°C-92°C), c = ?

Note that, the final temperature of water and the metal = 24°C

-{34 × c × (24°C-92°C)} = 22 × 4.18 × (24°C-19°C)

-{34 × c × (-68°C)} = 459.8

-{34 × c × -68} = 459.8

-{-2312c} = 459.8

+2312c = 459.8

c = 459.8/2312

c = 0.1988

The specific heat capacity of the metal is 0.1988 J/g°C

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The laboratory process of distillation does not involve
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C liquids with different boiling points, to distill you only use one liquid

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