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arlik [135]
3 years ago
14

A toy car is released at the top of an inclined plane. How does the car's energy change as it rolls down the inclined plane? tel

l me how u got your answer ☺️ this is science
A: both it's kinetic energy and potential increase

B: both it's kinetic energy and potential energy decrease

C; it's kinetic energy increases and it's potential energy decreases

D: it's kinetic energy decrease and it's potential energy increases​
Chemistry
1 answer:
sineoko [7]3 years ago
8 0

Answer:

C

Explanation:

at the inclined plane it possessed potential energy and minimal kinetic energy but once release it possess a kinetic energy

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Use the standard reaction enthalpies given below to determine ΔH°rxn for the following reaction: P4(g) + 10 Cl2(g) → 4PCl5(s) ΔH
Pie

Answer: -1835 kJ

Explanation:

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to Hess’s law, the chemical equation can be treated as algebraic expressions and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

PCl_5(s)\rightarrow PCl_3(g)+Cl_2(g)  \Delta H_1=+157kJ (1)

P_4(g)+6Cl_2\rightarrow 4PCl_3(g)  \Delta H_2=-1207J (2)

Net chemical equation:

P_4(g)+10Cl_2(g)\rightarrow 4PCl_5(s)  \Delta H=? (3)

Multiplying equation (1) by 4,  and reversing we get

4PCl_3(g)+4Cl_2(g)\rightarrow 4PCl_5(s)  \Delta H_4=4\times -157kJ=-628kJ (4)

Adding (2) and (4)

P_4(g)+10Cl_2(g)\rightarrow 4PCl_5(s)  \Delta H_3=\Delta H_2+\Delta H_4=-1207kJ-628kJ=-1835kJ  

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3 0
3 years ago
How much radium-226 will remain from a 20 gram sample after 4800 years?
ra1l [238]

Answer:

2.5 g mass of Ra-226 will remain after 4800 years.

Explanation:

Given data:

Mass of Ra-226 = 20 g

Sample remain after 4800 years = ?

Solution:

Half life of Ra-226 = 1600 years

Number of half lives passed = T elapsed / half life

Number of half lives passed = 4800 year / 1600 year

Number of half lives passed = 3

At time zero = 20 g

At first half life = 20 g/2 = 10 g

At 2nd half life = 10 g/2 = 5 g

At 3rd half life = 5 g/2 = 2.5 g

Thus, 2.5 g mass of Ra-226 will remain after 4800 years.

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3 years ago
How are different forms of energy related?
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Answer:

Pls rate Brainliest and See Explanation

Explanation:

A

6 0
3 years ago
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Determine the number of atoms present in 2 moles of argon gas
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2 moles x 6.02 x 10^23 maybe
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Draw the structure of ozone according to VSEPR theory. What would be its associated molecular geometry?
vodka [1.7K]

Answer: Ozone's molecular geometry can be described as bent.

Explanation:

The molecular geometry of the O3 groups has a trigonal planar arrangement.

Here is a quick explanation of the molecular geometry of O3 including a quick description of the O3 bond angles.

Examining the  Lewis structure of  O3 we can see that there are a pair of unbounded valence electrons at the top of the structure.

Based on VSEPR Theory (Valence Shell Electron Pair Repulsion Theory) these electrons will repel the electron clouds of the two oxygen atoms on the end.

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3 years ago
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