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Ilia_Sergeevich [38]
3 years ago
6

Heating oxygen difluoride gas yields oxygen gas and fluorine gas? Whats the balance chemical equation for this?

Chemistry
1 answer:
N76 [4]3 years ago
5 0
2OF2(g) —> O2(g) + 2F2(g) hope that helps
You might be interested in
A sample of hydrogen gas contains 4.8 x 1026 molecules of hydrogen. How many moles of hydrogen is this?
Travka [436]

Answer:

797.34 moles of H₂

Explanation:

From the question given above, the following data were obtained:

Number of molecules of H₂ = 4.8×10²⁶ molecules

Number of mole of H₂ =?

From Avogadro's hypothesis,

1 mole of H₂ = 6.02×10²³ molecules

With the above information, we can determine the number of mole of H₂ that contains 4.8×10²⁶ molecules as follow:

6.02×10²³ molecules = 1 mole of H₂

Therefore,

4.8×10²⁶ molecules = 4.8×10²⁶ / 6.02×10²³

4.8×10²⁶ molecules = 797.34 moles

Thus, 797.34 moles of H₂ contains 4.8×10²⁶ molecules.

4 0
2 years ago
Does anyone know how to do this?
rjkz [21]

Answer:

I know

Explanation:

Sike i dont know. Sorry man, but i dont know what that means - are you on crack? do you need therapy because I am a great therapist. Hmu if you'd like.

3 0
3 years ago
What is a compound in chemistry
nignag [31]
A compound is a substance formed when two or more chemical elements are chemically bonded together. In mixtures, the substances present are not chemically bonded together.
7 0
2 years ago
If an unknown liquid has a density of 0.756 g/mL and a mass of 2.00 g, what is its volume?
OverLord2011 [107]

Answer:

<h3>The answer is 2.65 mL</h3>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

volume =  \frac{mass}{density} \\

From the question

mass = 2 g

density = 0.756 g/mL

So we have

volume =  \frac{2}{0.756}  \\  = 2.645502...

We have the final answer as

<h3>2.65 mL</h3>

Hope this helps you

4 0
2 years ago
what is the limiting reactant in the reaction of 12.0 g of SO2 with 8.0 g of H2S and their reaction? what mass of sulfur will be
larisa86 [58]
The balanced equation for the reaction is as follows;
2H₂S + SO₂ —> 2H₂O + 3S
Stoichiometry of H₂S to SO₂ is 2:1
Limiting reactant is fully used up in the reaction and amount of product formed depends on amount of limiting reactant present.
Number of H₂S moles - 8.0 g / 34 g/mol = 0.24 mol of H₂S
Number of SO₂ moles = 12.0 g / 64 g/mol = 0.188 mol of SO₂
According to molar ratio of 2:1
If we assume H₂S to be the limiting reactant
2 mol of H₂S reacts with 1 mol of SO₂ 
Therefore 0.24 mol of H₂S requires - 1/2 x 0.24 = 0.12 mol of SO₂ 
But 0.188 mol of SO₂ is present therefore SO₂ is in excess and H₂S is the limiting reactant.
H₂S is the limiting reactant
Amount of S produced depends on amount of H₂S present
Stoichiometry of H₂S to S is 2:3
2 mol of H₂S forms 3 mol of S
Therefore 0.24 mol of H₂S forms - 3/2 x 0.24 mol = 0.36 mol of S
Mass of S produced = 0.36 mol x 32 g/mol = 11.5 g of S is produced
7 0
3 years ago
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