Answer:
797.34 moles of H₂
Explanation:
From the question given above, the following data were obtained:
Number of molecules of H₂ = 4.8×10²⁶ molecules
Number of mole of H₂ =?
From Avogadro's hypothesis,
1 mole of H₂ = 6.02×10²³ molecules
With the above information, we can determine the number of mole of H₂ that contains 4.8×10²⁶ molecules as follow:
6.02×10²³ molecules = 1 mole of H₂
Therefore,
4.8×10²⁶ molecules = 4.8×10²⁶ / 6.02×10²³
4.8×10²⁶ molecules = 797.34 moles
Thus, 797.34 moles of H₂ contains 4.8×10²⁶ molecules.
Answer:
I know
Explanation:
Sike i dont know. Sorry man, but i dont know what that means - are you on crack? do you need therapy because I am a great therapist. Hmu if you'd like.
A compound is a substance formed when two or more chemical elements are chemically bonded together. In mixtures, the substances present are not chemically bonded together.
Answer:
<h3>The answer is 2.65 mL</h3>
Explanation:
The volume of a substance when given the density and mass can be found by using the formula

From the question
mass = 2 g
density = 0.756 g/mL
So we have

We have the final answer as
<h3>2.65 mL</h3>
Hope this helps you
The balanced equation for the reaction is as follows;
2H₂S + SO₂ —> 2H₂O + 3S
Stoichiometry of H₂S to SO₂ is 2:1
Limiting reactant is fully used up in the reaction and amount of product formed depends on amount of limiting reactant present.
Number of H₂S moles - 8.0 g / 34 g/mol = 0.24 mol of H₂S
Number of SO₂ moles = 12.0 g / 64 g/mol = 0.188 mol of SO₂
According to molar ratio of 2:1
If we assume H₂S to be the limiting reactant
2 mol of H₂S reacts with 1 mol of SO₂
Therefore 0.24 mol of H₂S requires - 1/2 x 0.24 = 0.12 mol of SO₂
But 0.188 mol of SO₂ is present therefore SO₂ is in excess and H₂S is the limiting reactant.
H₂S is the limiting reactant
Amount of S produced depends on amount of H₂S present
Stoichiometry of H₂S to S is 2:3
2 mol of H₂S forms 3 mol of S
Therefore 0.24 mol of H₂S forms - 3/2 x 0.24 mol = 0.36 mol of S
Mass of S produced = 0.36 mol x 32 g/mol = 11.5 g of S is produced