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3 years ago

Heating oxygen difluoride gas yields oxygen gas and fluorine gas? Whats the balance chemical equation for this?

Chemistry

1 answer:

N76 [4]3 years ago

5 0

2OF2(g) —> O2(g) + 2F2(g) hope that helps

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1. What is the wave speed of a wave that has a frequency of 100 Hz and a wavelength of 0.30 m?

Sav [38]

Wave speed = frequency x wavelength
= 100 x 0.3
= 30 m/s.

Hope this helps!

5 0

3 years ago

Read 2 more answers

CaCO3(s)+2H*(aq) →Ca2+ (aq)+H2001+CO262)

Effectus [21]

Answer:CO2(g) will be formed at a faster rate in experiment 2 because more H+ particles can react per unit time

Explanation:

8 0

3 years ago

Vertical columns in the periodic table indicate what information? . . . A.. periods. . . B.. liquids. . . C.. synthetic elements

kozerog [31]

The answer is D. groups and families

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3 years ago

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Calculate the concentration in mol/L, M, of an aqueous sugar solution with a concentration of 23.5% (w/w) and density of 1.005 g

Temka [501]

Answer:

The concentration in mol/L is 0.683M

Explanation:

23.5% (w/w)

This data means that in 100 g of solution, we have 23.5 grams of solute.

From this point, we can calculate the moles of sugar.

Moles = Mass / Molar mass

Moles = 23.5 g /342.30 g/m

Moles = 0.068 moles

Density data make us know, the volume of our solution.

solution δ = solution mass / solution volume

δ = 1.005 g/mL = 100 g / solution volume

solution volume = 100g / 1.005 g/ml

solution volume = 99.5 mL

In conclusion, 0.068 moles are in 99.5 mL

Molarity (M) is mol/L

Let's convert 99.5 mL in L

99.5 mL / 1000 = 0.0995 L

0.068 m / 0.0995L = 0.683

If we convert moles in mmoles, we can also get Molarity (M)

mmoles / mL = M

0.068 moles . 1000 = 68 mmoles

68 mmmoles / 99.5mL = 0.683

8 0

3 years ago

Question: What is the molar concentration of 1.29 mol of KCL dissolved in 350 mL of solution?

STatiana [176]

Answer:

M = 3.69 M.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the molar concentration of the 1.29 moles of KCl in 350 mL of solution by recalling the mathematical definition of molarity as the division of the moles by the volume in liters, in this case 0.350 L; thus, we proceed as follows:

$M=\frac{1.29mol}{0.350L}\\\\M=3.69M$

Which gives molar units, M, or just mol/L.

Regards!

8 0

3 years ago