Answer:
Element
Explanation:
A chemical element is a substance that contains only one type of atom, which is the smallest particle of an element
Answer:
Explanation:
<u>1) Arrhenius equation</u>
Arrhenius equation shows the relation between activation energy, temperature, and the equilibrium constant.
This is the equation:
Where:
- K is the equilibrium constant,
- A is the frequency factor,
- Ea is the activation energy (in J/mol),
- T is the temperature in kelvins (K), and
- R is the universal constant.
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<u>2) Substitute, using the right units, and compute:</u>
- A = 4.20 × 10¹² (dimensionless)
- Ea = 67.0 kJ/mol = 67,000 J/mol
- T = 24.0°C = 24.0 + 273.15 K = 297.15 K
- R = 8.314 J/K mol
Answer:
2.05mg Fe/ g sample
Explanation:
In all chemical extractions you lose analyte. Recovery standards are a way to know how many analyte you lose.
In the problem you recover 3.5mg Fe / 1.0101g sample: <em>3.465mg Fe / g sample. </em>As real concentration of the standard is 4.0 mg / g of sample the percent of recovery extraction is:
3.465 / 4×100 = <em>86,6%</em>
As the recovery of your sample was 1.7mg Fe / 0.9582g, the Iron present in your sample is:
1.7mg Fe / 0.9582g sample× (100/86.6) = <em>2.05mg Fe / g sample</em>
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I hope it helps!
Answer:
A neutralization reaction between an acid and a metal hydroxide produces salt and water.
Explanation:
In a neutralization reaction, an acid and a base are combined according to the following example (hydrochloric acid and sodium hydroxide):
HCl + NaOH ---> H20 + NaCl
They are generated as products: water and a salt, in this case sodium chloride.
Answer:
3CaBr2 + 2LI3PO4 - > Ca3(PO4) 2 + 6LiBr
Explanation:
The first one I did was PO4. There are two on the right side, so I added 2 to Li3PO4 on the other side. That balanced the PO4s and then gave me 6 Lithiums so I balanced that one next on the right side. I added 6 to LiBr which balanced the Li but then gave me 6 Br, so I finished it off by adding 3 in front of CaBr2 which balanced the calcium and bromines.
Here was the process:
CaBr2+2Li3PO4 -> Ca3(PO4)2+LiBr
Balances PO4 (2on both sides)
CaBr2+2Li3PO4 -> Ca3(PO4)2+6LiBr
Balances Lithiums (6 on each side)
3CaBr2+2Li3PO4 -> Ca3(PO4)2+6LiBr
Balances Calciums and Bromines (3 Calciums and 6 Bromines each side)
Hope this helped!
