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pashok25 [27]
3 years ago
14

About the instruction that marko gave to hinano

Chemistry
1 answer:
Elden [556K]3 years ago
3 0

Answer: he gave him a map of somewhere

Explanation:

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Which of the following statements is true
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Facing the wind. A) windward B) subaric C) monsoon D) biotic
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STEP-by STEP EXPLANATION
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PLEASE HELP I HAVE THIS TEST TOMORROW AM GIVING MORE POINTS THAN I SHOULD
zavuch27 [327]

Answer:

41.11 g of Ca(OH)2.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

CaO + H2O —> Ca(OH)2

Next, we shall determine the masses of CaO and H2O that reacted and the mass of Ca(OH)2 produced from the balanced equation. This can be obtained as follow:

Molar mass of CaO = 40 + 16 = 56 g/mol

Mass of CaO from the balanced equation = 1 × 56 = 56 g

Molar mass of H2O = (2x1) + 16

= 2 + 16

= 18 g/mol

Mass of H2O from the balanced equation = 1 × 18 = 18 g

Molar mass of Ca(OH)2 = 40 + 2(16 + 1)

= 40 + 2(17)

= 40 + 34

= 74 g/mol

Mass of Ca(OH)2 from the balanced equation = 1 × 74 = 74 g

From the balanced equation above,

56 g of CaO reacted with 18 g of H2O to produce 74 g of Ca(OH)2.

Finally, we obtained the mass of calcium hydroxide, Ca(OH)2 produced from the reaction of 33 g of CaO and 10 g of H2O. This can be obtained as follow:

From the question given above, we were told that when 33 g of CaO and 10 g of H2O reacted, 2 g of CaO were remaining. This implies that H2O is the limiting reactant and CaO is the excess reactant.

Thus, we shall use the limiting reactant to determine the mass of calcium hydroxide, Ca(OH)2 produced because it will give the maximum yield as all of it is consumed in the reaction.

The limiting reactant is H2O and the mass of calcium hydroxide, Ca(OH)2 produced can be obtained as follow:

From the balanced equation above,

18 g of H2O reacted to produce 74 g of Ca(OH)2.

Therefore, 10 g of H2O will react to produce = (10 × 74)/18 = 41.11 g of Ca(OH)2.

Therefore, 41.11 g of Ca(OH)2 were obtained from the reaction.

3 0
3 years ago
A quantity of gas occupies a volume of 804 mL at a temperature of 27 °C. At what temperature will the
irga5000 [103]

Answer:

T₂ = 150 K

Explanation:

Given data:

Initial volume of gas = 804 mL

Initial temperature = 27°C (27+273=300 K)

Final temperature = ?

Final volume = 402 mL

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

T₂ = V₂T₁/V₁  

T₂ = 402 mL × 300 K / 804 mL

T₂ = 120,600 mL.K / 804 mL

T₂ = 150 K

3 0
3 years ago
Which of the following elements is the most reactive?    A. Arsenic (As)    B. Sulfur (S)    C. Fluorine (F)    D. Carbon (C
adell [148]
I think its a but i could be wrong

4 0
3 years ago
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