Answer:
<em>A solution containing 60 grams of nano3 completely dissolved in 50. Grams of water at 50°c is classified as being</em> <u>supersaturaded</u>
Explanation:
This question is about solubility.
Regarding solubility, the solutions may be classified as:
- Unsaturated: the concentration is below the maximum concentration permited at the given temperature.
- Saturated: the concentration is the maximum permitted at the given temperature, under normal conditions.
- Supersaturated: the concentration has overcome the maximum permitted at the given temperature. This is possible only under special conditions and is a very unstable state.
Each substance has its own, unique solubility properties. So, in order to tell the state of the solution you need to compare with either solubility tables, or solubility curves; or run you own experiments.
- In internet you can find the solubility curve of NaNO₃ showing the solubility for a wide range of temperatures.
- In such curve the solubility of NaNO₃ at 50°C is about 115 g of NaNO₃ per 100 g of water.
- Hence, do the proportion to determine the amount of solute that can be dissolved in 50 grams of water at 50°CÑ
115 g NaNO₃ / 100 g H₂O = x / 50 g H₂O ⇒ x = 57.5 g NaNO₃
- <u>Conclusion</u>: 50 grams of water can contain 57.5 g of NaNO₃ dissolved; so, <em>a solution containing 60 g of NaNO₃ completely dissolved in 50 grams of water is supersaturated.</em>
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Answer:
In the first paragraph, name a theme of Paul Laurence Dunbar's poem "Sympathy," and explain how it develops, citing specific examples
Explanation:
The volume of a box with length 25 cm, height 25 cm and width 1.0 m is 0.0625m³.
Volume of the box which is a cuboid can be calculated by multiplying the length, breadth and height of the given box.
Volume of the box is given by the product of the length of the box, Height of the box and Breadth or width of the box.
Since, the box is a cuboid, hence the formula is given by the products of length, breadth and height.
Given,
length of the box= 25cm = 0.25m
Height of the box =25cm = 0.25m
width of the box= 1m
Volume = length × width × height of box
Volume = 0.25 × 0.25 × 1
Volume = 0.0625m³
The volume of the box is 0.0625m³.
Learn more about Volume here, brainly.com/question/23118276
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