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enot [183]
3 years ago
8

PLEASE HELP DUE SOON

Chemistry
1 answer:
Alona [7]3 years ago
7 0

Answer:

Because energy is conserved, the kinetic energy of a block at the bottom of a frictionless

ramp is equal to the gravitational potential energy of the block at the top of the ramp. This

value is proportional to the square of the block’s velocity at the bottom of the ramp.

Therefore, the block’s final velocity depends on the height of the ramp but not the steepness

of the ramp

Explanation:

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In the electron cloud model of the atom, an orbital is defined as the most probable(1) charge of an electron
Galina-37 [17]

The correct answer would be 3.) Location of an electron
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Classify each element as a metal, nonmetal, or semimetal. br in cr ca drag the appropriate items to their respective bins. view
goldenfox [79]
Below is the distribution of given elements and additional elements in their respective bins.

Iron, Magnesium, Aluminium, Calcium, Chromium and Indium are classified as Metals due to their hardness, conduction of current and heat, Solid state, formation of metallic bonding and prefers to form cations e.t.c

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6 0
3 years ago
(WILL GIVE BRAINLIEST IF YOU ANSWER ALL 4) Chemistry
Kitty [74]

Answer:

See explanations

Explanation:

a. Molarity = moles/Volume in Liters = 5moles/2Liters = 2.5M in NaCl

b. Freezing Pt Depression

     1. Sprinkling salt on icy surfaces

    2. Using antifreeze in automobile cooling systems

    3. <em>Not an application </em>

    4. Using salt to make ice cream

c. pOH = -log[OHˉ] = -log(1x10ˉ¹⁰) = -(-10) = 10 => pH = 14 – pOH = 14 – 10 = 4

d. H₂O + NH₃ => NH₄⁺ + OHˉ => Bronsted Acid is H₂O  (proton donor)

5 0
3 years ago
Consider the following reaction:
adell [148]

Answer:

1. d[H₂O₂]/dt = -6.6 × 10⁻³ mol·L⁻¹s⁻¹; d[H₂O]/dt = 6.6 × 10⁻³ mol·L⁻¹s⁻¹

2. 0.58 mol

Explanation:

1.Given ΔO₂/Δt…

    2H₂O₂     ⟶      2H₂O     +     O₂

-½d[H₂O₂]/dt = +½d[H₂O]/dt = d[O₂]/dt  

d[H₂O₂]/dt = -2d[O₂]/dt = -2 × 3.3 × 10⁻³ mol·L⁻¹s⁻¹ = -6.6 × 10⁻³mol·L⁻¹s⁻¹

 d[H₂O]/dt =  2d[O₂]/dt =  2 × 3.3 × 10⁻³ mol·L⁻¹s⁻¹ =  6.6 × 10⁻³mol·L⁻¹s⁻¹

2. Moles of O₂  

(a) Initial moles of H₂O₂

\text{Moles} = \text{1.5 L} \times \dfrac{\text{1.0 mol}}{\text{1 L}} = \text{1.5 mol }

(b) Final moles of H₂O₂

The concentration of H₂O₂ has dropped to 0.22 mol·L⁻¹.

\text{Moles} = \text{1.5 L} \times \dfrac{\text{0.22 mol}}{\text{1 L}} = \text{0.33 mol }

(c) Moles of H₂O₂ reacted

Moles reacted = 1.5 mol - 0.33 mol = 1.17 mol

(d) Moles of O₂ formed

\text{Moles of O}_{2} = \text{1.33 mol H$_{2}$O}_{2} \times \dfrac{\text{1 mol O}_{2}}{\text{2 mol H$_{2}$O}_{2}} = \textbf{0.58 mol O}_{2}\\\\\text{The amount of oxygen formed is $\large \boxed{\textbf{0.58 mol}}$}

8 0
3 years ago
Finding the pH for [H+] = 9.4 * 10-3 M?
saul85 [17]

Answer:

pH = 2.0

Explanation:

To find the pH of a solution, take the -log[H+]. In this case, the -log(9.4 x 10^-3) equals 2.02687 which makes 2.0 when accounting for significant figures.

3 0
3 years ago
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