To increase the energy of the emitted electrons, the frequency of the incident light on the metal must be increased.
<h3>What is energy of emitted electron?</h3>
The maximum energy of an emitted electron is equal to the energy of a photon for frequency f (E = hf ), minus the energy required to eject an electron from the metal's surface, also known as work function.
Ee = E - W
<h3>Energy of the emitted electron</h3>
The energy of emitted electrons based on the research of Albert Einstein is given as;
E = hf
where;
- h is planck's constant
- f is frequency of incident light on the metal
Thus, to increase the energy of the emitted electrons, the frequency of the incident light on the metal must be increased.
Learn more about energy of electron here: brainly.com/question/11316046
#SPJ1
Answer:
1.72x10⁻⁵ g
Explanation:
To solve this problem we use the PV=nRT equation, where:
- R = 0.082 atm·L·mol⁻¹·K⁻¹
- T = 25 °C ⇒ (25+273.16) = 298.16 K
And we <u>solve for n</u>:
- 1 atm * 5.7x10⁶ L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 298.16 K
Finally we <u>convert moles of helium to grams</u>, using its <em>molar mass</em>:
- 4.29x10⁻⁶ mol * 4 g/mol = 1.72x10⁻⁵ g
Answer:
Explanation:
Explanation:
All you have to do here is use the ideal gas law equation, which looks like this
P
V
=
n
R
T
−−−−−−−−−−
Here
P
is the pressure of the gas
V
is the volume it occupies
n
is the number of moles of gas present in the sample
R
is the universal gas constant, equal to
0.0821
atm L
mol K
T
is the absolute temperature of the gas
Rearrange the equation to solve for
T
P
V
=
n
R
T
⇒
T
=
P
V
n
R
Before plugging in your values, make sure that the units given to you match those used in the expression of the universal gas constant.
In this case, the volume is given in liters and the pressure in atmospheres, so you're good to go.
Plug in your values to find
T
=
3.10
atm
⋅
64.51
L
9.69
moles
⋅
0.0821
atm
⋅
L
mol
⋅
K
T
=
251 K
−−−−−−−−−
The answer is rounded to three
(i’m not very good at writing but use this as an idea)
changing the told would mess up the amount a daylight/nighttime because they’d be at a different angle from the sun
