13. Given the table representing the subatomic particles

What was Ernest Rutherford's experiment?

Dafna1 [17]

Answer:

C. He shot tiny alpha particles through a piece of gold foil.

Explanation:

In the year 1911, Ernest Rutherford performed the gold foil experiment which gave a deeper perspective to the structure of an atom.

He simply collided a thin gold foil with an alpha particle which he generated from a radioactive source. He discovered that most of the alpha particles passed through the thin gold foil but a few were deflected back. His discovery led to the proposition of the nuclear model of the atom.

6 0

3 years ago

A nugget of GOLD has a mass 9.66 gram and a volume of 0.5 cm3, It's density is<br>grams/cm3 *

dalvyx [7]

Answer:

P=19.32g/cm³

Explanation:

m=9.66g

v=0.5cm³

P=mass/volume (density formula)

=9.66/0.5

=19.32g/cm³

4 0

3 years ago

Determine the value of the equilibrium constant, KgoalKgoalK_goal, for the reaction CO2(g)⇌C(s)+O2(g)CO2(g)⇌C(s)+O2(g), Kgoal=?

NISA [10]

Answer:

The value of the equilibrium constant for reaction asked is $1.24\times 10^{-7}$ .

Explanation:

$CO_2(g)\rightleftharpoons C(s)+O_2(g)$

$K_{goal}=?$

$K_{goal}=\frac{[C][O_2]}{[CO_2]}$

$2CO_2(g)+2H_2O(l)\rightleftharpoons CH_3COOH(l)+2O_2(g)$ ..[1]

$K_1=\frac{[CH_3COOH][O_2]^2}{[CO_2]^2[H_2O]^2}$

$2H_2(g)+O2(g)\rightleftharpoons 2H_2O(l)$ ..[2]

$K_2=\frac{[H_2O]^2}{[H_2]^2[O_2]}$

$CH_3COOH(l)\rightleftharpoons 2C(s)+2H_2(g)+O_2(g)$ ..[3]

$K_3=\frac{[C]^2[H_2]^2[O_2]}{[CH_3COOH]}$

[1] + [2] + [3]

$2CO_2(g)\rightleftharpoons 2C(s)+2O_2(g)$

( on adding the equilibrium constant will get multiplied with each other)

$K=K_1\times K_2\times K_3$

$K=5.40\times 10^{-16}\times 1.06\times 10^{10}\times 2.68\times 10^{-9}$

$K=1.53\times 10^{-14}$

$K=\frac{[C]^2[O_2]^2}{[CO_2]^2}$

On comparing the K and $K_{goal}$ :

$K^2=K_{goal}$

$K_{goal}=\sqrt{K}=\sqrt{1.53\times 10^{-14}}=1.24\times 10^{-7}$

The value of the equilibrium constant for reaction asked is $1.24\times 10^{-7}$ .

4 0

3 years ago

A persistent or nonvolatile chemical agent can: Select one: a. explode without warning and releases gases. b. remain in the envi

avanturin [10]

Answer: A persistent or non-volatile chemical agent can remain on a surface for more than 24 hours.

Explanation:

Non-volatile substance is defined as the one which does not readily evaporate into its surrounding. Generally, a non-volatile substance has strong intermolecular forces between its molecules.

A non-volatile substance will take more than 24 hours to remain on the surface.

On the other hand, a substance with weak intermolecular forces present in its molecules will readily evaporate into the atmosphere.

For example, acetic acid is a volatile substance and quickly evaporates into the atmosphere.

Thus, we can conclude that a persistent or non-volatile chemical agent can remain on a surface for more than 24 hours.

5 0

3 years ago

Example of electrovalent bond

olchik [2.2K]

Explanation:

<h2>hope it helps.</h2><h2>stay safe healthy and happy..</h2>

4 0

3 years ago

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