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bulgar [2K]
3 years ago
9

Directions: Show all of your work for each of the following problems.

Chemistry
1 answer:
AysviL [449]3 years ago
8 0

Answer:

<h3>3.Ba=2</h3><h3>4.Ni=2...PO4=3</h3><h3>5.Al=3...CrO4=2</h3><h3>6.NH4=1...SO4=2</h3>
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I believe it's A generally increases may be wrong

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Since in the forward reaction, H2S is giving a proton away (being the acid) and then CH3NH2 accepting that proton given (being the base).
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4 years ago
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The second messenger cyclic AMP (cAMP) is synthesized from ATP by the activity of the enzyme adenylyl cyclase. Cyclic AMP, in tu
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Answer: 1. Cyclic AMP(cAMP) concentration increases;

2. cAMP then binds to the two regulatory subunits;

3. A change in the conformation of enzyme results. The autoinhibitory sequences move away from the active site of the catalytic subunits;

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(Note: The question did not list the steps to be placed in the correct order)

Explanation:

The inactive form of Protein Kinase A (PKA) contains two identical sub-units (C) and two identical regulatory sub-units (R). Two auto-inhibitory sequences of the regulatory subunits occupy the catalytic sites of the catalytic subunits. After the reaction of adenylyl cyclase, this inactive form of PKA is activated in the following steps:

1.<em> </em><em>Cyclic AMP</em><em>(</em><em>cAMP</em><em>) concentration increases;</em>

<em>2. </em><em>cAMP</em><em> then binds to the two regulatory subunits;</em>

<em>3. A change in the conformation of enzyme results. The autoinhibitory sequences move away from the active site of the catalytic subunits;</em>

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8 0
3 years ago
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Hence, the bond length in HCl is 125 pm.

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