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3 years ago

10

How to draw the ray diagram? Pls answer

1 answer:

weqwewe [10]3 years ago

7 0

1. Pick a point on the top of the object and draw two incident rays traveling towards the mirror. Using a straight edge, accurately draw one ray so that it passes exactly through the focal point on the way to the mirror. Draw the second ray such that it travels exactly parallel to the principal axis.

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A table exerts a 4.0 Newton force on a book which lies at rest on its top. The force exerted by the book on the table is

SOVA2 [1]

I believe the correct answer from the choices listed above is the third option. <span>The force exerted by the book on the table is equal to the force exerted by the table which is 4.0 N. The book does not move so it must be that the forces are balanced. Hope this answers the question.</span>

4 0

2 years ago

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From a hot air balloon that is at rest at a certain height, a projectile is launched horizontally at 30m / s, how fast will it h

Yuki888 [10]

Answer:

A. 50 m/s

Explanation:

Given in the y direction:

v₀ = 0 m/s

a = 10 m/s²

t = 4 s

Find: v

v = at + v₀

v = (10 m/s²) (4 s) + 0 m/s

v = 40 m/s

In the x direction, the velocity is constant at 30 m/s.

The overall speed is:

v² = (30 m/s)² + (40 m/s)²

v = 50 m/s

3 0

2 years ago

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Kinetic friction acts on a baseball player sliding into first base. Will the player's velocity change?

Law Incorporation [45]

Yes, his velocity will decrease the further he slides.

7 0

2 years ago

What is TRUE about cancer cells?

Artist 52 [7]

Answer:

Explanation:

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2 years ago

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A trooper is moving due south along the freeway at a speed of 30.1 m/s when a red car passes the trooper. The red car moves with

romanna [79]

Answer:

The correct answer to the following question will be "41.87 m".

Explanation:

The given values are:

The speed of trooper = $30.1 \ m/s$

The velocity of red car = $45.4 \ m/s$

Now,

A red car goes as far as possible until the speed or velocity of the troops is the same as that of of the red car at

$t=\frac{45-30}{2.7}$ (∵ $time=\frac{distance}{time}$ )

$t=5.56 \ sec$

then,

The distance covered by trooper,

$t1=30\times 5.56+\frac{1}{2}\times 2.7\times (5.56)^2$

$=208.33 \ m$

The distance covered by red car,

= $45\times 5.56$

= $250.2 \ m$

Maximum distance = $250.2-208.33$

= $41.87 \ m$

6 0

2 years ago