Given
m1(mass of the first object): 55 Kg
m2 (mass of the second object): 55 Kg
v1 (velocity of the first object): 4.5 m/s
v2 (velocity of the second object): ?
m3(mass of the object dropped): 2.5 Kg
The law of conservation of momentum states that when two bodies collide with each other, the momentum of the two bodies before the collision is equal to the momentum after the collision. This can be mathemetaically represented as below:
Pa= Pb
Where Pa is the momentum before collision and Pb is the momentum after collision.
Now applying this law for the above problem we get
Momentum before collision= momentum after collision.
Momentum before collision = (m1+m2) x v1 =(55+5)x 4.5 = 270 Kgm/s
Momentum after collision = (m1+m2+m3) x v2 =(55+5+2.5) x v2
Now we know that Momentum before collision= momentum after collision.
Hence we get
270 = 62.5 v2
v2 = 4.32 m/s
Then the object moves in a circle.
<h2>
Answer:</h2>
<u><em>Agriculture is the science, the practice of cultivating the soil, art, producing crops, raising livestock, and in varying degrees the preparation and marketing of the resulting products cleared the land to use for agriculture.</em></u>
<h2>
Explanation: </h2>
<em>This is what I found during my research and I hope this helps. Correct me if I am incorrect! Have a good one. </em>
<h2>
≧◉◡◉≦</h2>
