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tresset_1 [31]
3 years ago
9

The diagram below shows two bowling balls, A and B, each having a mass of 7.0 kg, placed 2.00 m apart between their centers.

Physics
1 answer:
AVprozaik [17]3 years ago
7 0

Answer:

F = 1.63 x 10⁻⁹ N

Explanation:

Complete question is as follows:

The diagram below shows two bowling balls, A and B, each having a mass of 7.0 kg, placed 2.00 m apart between their centers. Find the magnitude of Gravitational Force?

Answer:

The gravitational force is given by Newton's Gravitational Law as follows:

F = Gm₁m₂/r²

where,

F = Gravitational Force = ?

G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²

m₁ = m₂ = mass of each ball = 7 kg

r = distance between balls = 2 m

Therefore,

F = (6.67 x 10⁻¹¹ N.m²/kg²)(7 kg)(7 kg)/(2 m)²

<u>F = 1.63 x 10⁻⁹ N</u>

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sineoko [7]

Answer:

The force of gravity = 40 N

Explanation:

Given that,

The mass of a ball, m = 10 kg

The acceleration due to gravity on the surface of Mars, a = 4 m/s²

We need to find the force of gravity of the ball on Mars. The force of gravity on an object is given by :

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Substitute all the values,

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6 0
3 years ago
Light of wavelength 578.0 nm is incident on a narrow slit. The diffraction pattern is viewed on a screen 62.5 cm from the slit.
yaroslaw [1]

Answer:

80.6\mu m

Explanation:

When light passes through a narrow slit, it produces a diffraction pattern on a distant screen, consisting of several bright fringes (constructive interference) alternated with dark fringes (destructive interference).

The formula to calculate the position of the m-th maximum in the diffraction pattern produced in the screen is:

y=\frac{m\lambda D}{d}

where

y is the distance of the m-th maximum from the central maximum (m = 0)

\lambda is the wavelength of light used

D is the distance of the screen from the slit

d is the width of the slit

In this problem, we have:

\lambda=578.0 nm = 578\cdot 10^{-9} m is the wavelength

D = 62.5 cm = 0.625 m is the distance of the screen

We know that the distance between the third order maximum (m=3) and the central maximum is 1.35 cm (0.0135 m), which means that

y_3 = 0.0135 m

For

m = 3

Therefore, rearranging the equation for d, we find the width of the slit:

d=\frac{m\lambda D}{y_3}=\frac{(3)(578\cdot 10^{-9})(0.625)}{0.0135}=80.3\cdot 10^{-6} m=80.6\mu m

8 0
4 years ago
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stiks02 [169]

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Explanation:

It’s just a guess.

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Answer:

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