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NARA [144]
2 years ago
6

Explain on any two modifications that you would expect to use for the thermos flask which would enable it to be handier/helpful.

Physics
2 answers:
LuckyWell [14K]2 years ago
7 0

Answer:

The two modifications in the Thermos flask which would enable it to be more helpful:  

1) To have an internal temperature indicator that indicates temperature.  

2) A wireless rechargeable battery (USB connector)  

Pls mark me brainliest.  

quester [9]2 years ago
5 0

Here, we are required to explain any two modifications to use for the thermos flask which would enable it to be handier/ helpful.

  1. The presence of a built-in temperature monitoring system would enable it to be handier/helpful.
  2. The presence of a built-in solar panel on the thermos flask cover for harvesting solar energy which may further be converted to electric energy and dispensed through USB ports.

Value addition is important in improving existing products such that they become handier/helpful.

Therefore, the 2 modifications stated above can be used for the Thermos flask to enable it to be handier/handler.

Read more:

brainly.com/question/24019227

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The latent heat of fusion of a substance is the amount of energy associated
kicyunya [14]

Answer:

The Answer is A Hope I helped you :D Have a Great Day!

Explanation:

6 0
2 years ago
A mass m neutron has elastic collision with a mass m'
hoa [83]

Answer:

The neutron loses all of its kinetic energy to nucleus.

Explanation:

Given:

Mass of neutron is 'm' and mass of nucleus is 'm'.

The type of collision is elastic collision.

In elastic collision, there is no loss in kinetic energy of the system. So, total kinetic energy is conserved. Also, the total momentum of the system is conserved.

Here, the nucleus is still. So, its initial kinetic energy is 0. So, the total initial kinetic energy will be equal to kinetic energy of the neutron only.

Now, final kinetic energy of the system will be equal to the initial kinetic energy.

Now, as the nucleus was at rest initially, so the final kinetic energy of the nucleus will be equal to the initial kinetic energy of the neutron.

Thus, all the kinetic energy of the neutron will be transferred to the nucleus and the neutron will come to rest after collision.

Therefore, the neutron loses all of its kinetic energy to nucleus.

5 0
3 years ago
David is investigating the properties of soil using the sample shown.
xenn [34]

Although the sample is not shown in this question, we can conclude that it would be reasonably easy for David to provide evidence of the color, consistency, temperature, and texture of the soil.

<h3 />

<h3>What are these properties an example of?</h3>

These are all examples of the physical properties of a sample. Since we cannot see the sample that David is using, it would be safest to assume that he would have no trouble providing evidence as to the physical properties of the soil, the:

  • Color
  • Consistency
  • Temperature
  • Texture

are all examples of this.

Therefore, we can confirm that David can provide evidence of the color, consistency, temperature, and texture of the soil.

To learn more about physical properties visit:

brainly.com/question/24632287?referrer=searchResults

7 0
2 years ago
What is the speed of a wave if the wavelength is 100m and the period is 20s
Sergio039 [100]
I don’t think I’m right but I want to say 500 m/s
4 0
3 years ago
Read 2 more answers
A spy satellite uses a telescope with a 1.7-m-diameter mirror. It orbits the earth at a height of 180 km.
WINSTONCH [101]

Answer: the minimum spacing that must be there between two objects on the earth's surface if they are to be resolved as distinct objects by this telescope 6.45 cm

Explanation:

Given that;

diameter of the mirror d = 1.7 m

height h = 180 km = 180 × 10³ m

wavelength λ = 500 nm = 5 × 10⁻⁹ m

Now Angular separation from the peak of the central maximum is expressed as;

sin∅= 1.22 λ / d

sin∅ = (1.22 × 5 × 10⁻⁹) / 1.7

 sin∅ = 3.588 × 10⁻⁷

we know that;

 sin∅  = object separation / distance from telescope

object separation =   sin∅ × distance from telescope

object separation = 3.588 × 10⁻⁷  × 180 × 10³

object separation =6.45 × 10⁻² m

then we convert to centimeter

object separation = 6.45 cm

Therefore the minimum spacing that must be there between two objects on the earth's surface if they are to be resolved as distinct objects by this telescope 6.45 cm

5 0
3 years ago
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