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2 years ago

Explain on any two modifications that you would expect to use for the thermos flask which would enable it to be handier/helpful.

Physics

2 answers:

LuckyWell [14K]2 years ago

7 0

Answer:

The two modifications in the Thermos flask which would enable it to be more helpful:

1) To have an internal temperature indicator that indicates temperature.

2) A wireless rechargeable battery (USB connector)

Pls mark me brainliest.

quester [9]2 years ago

5 0

Here, we are required to explain any two modifications to use for the thermos flask which would enable it to be handier/ helpful.

The presence of a built-in temperature monitoring system would enable it to be handier/helpful.
The presence of a built-in solar panel on the thermos flask cover for harvesting solar energy which may further be converted to electric energy and dispensed through USB ports.

Value addition is important in improving existing products such that they become handier/helpful.

Therefore, the 2 modifications stated above can be used for the Thermos flask to enable it to be handier/handler.

Read more:

brainly.com/question/24019227

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A baseball m=.34kg is spun vertically on a massless string of length l=.52m. the string can only support a tension of tmax=9.9n

larisa86 [58]

<span>4.5 m/s This is an exercise in centripetal force. The formula is F = mv^2/r where m = mass v = velocity r = radius Now to add a little extra twist to the fun, we're swinging in a vertical plane so gravity comes into effect. At the bottom of the swing, the force experienced is the F above plus the acceleration due to gravity, and at the top of the swing, the force experienced is the F above minus the acceleration due to gravity. I will assume you're capable of changing the velocity of the ball quickly so you don't break the string at the bottom of the loop. Let's determine the force we get from gravity. 0.34 kg * 9.8 m/s^2 = 3.332 kg m/s^2 = 3.332 N Since we're getting some help from gravity, the force that will break the string is 9.9 N + 3.332 N = 13.232 N Plug known values into formula. F = mv^2/r 13.232 kg m/s^2 = 0.34 kg V^2 / 0.52 m 6.88064 kg m^2/s^2 = 0.34 kg V^2 20.23717647 m^2/s^2 = V^2 4.498574938 m/s = V Rounding to 2 significant figures gives 4.5 m/s The actual obtainable velocity is likely to be much lower. You may handle 13.232 N at the top of the swing where gravity is helping to keep you from breaking the string, but at the bottom of the swing, you can only handle 6.568 N where gravity is working against you, making the string easier to break.</span>

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3 years ago

Read 2 more answers

rickey approaches third base. He dives head first, hitting the ground at 6.75 m/s and reaching the base at 5.91 m/s in 2.5 secon

Gekata [30.6K]

Answer:

15.825 m

Explanation:

t = Time taken = 2.5 s

u = Initial velocity = 6.75 m/s

v = Final velocity = 5.91 m/s

s = Displacement

a = Acceleration

Equation of motion

$v=u+at\\\Rightarrow a=\frac{v-u}{t}\\\Rightarrow a=\frac{5.91-6.75}{2.5}\\\Rightarrow a=-0.336\ m/s^2$

$v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{5.91^2-6.75^2}{2\times -0.336}\\\Rightarrow s=15.825\ m$

The distance Rickey slides across the ground before touching the base is 15.825 m

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2 years ago

When the light from the sun warms the ground, the transfer of energy of heat is called...

NISA [10]

C. Radiation Hope this helps and You're welcome. :3

3 0

2 years ago

Read 2 more answers

The temperature of a solution will be estimated by taking n independent readings and averaging them. Each reading is unbiased, w

Viktor [21]

Answer:

68 readings.

Explanation:

We need to take this problem as a statistic problem where the normal distribution table help us.

We can start considerating that X is the temperature of the solution, then

$0.9 = P(|\bar{x}-\mu|$

$0.9 = P(\frac{|\bar{x}-\mu|}{\frac{\sigma}{\sqrt{n}}}$

$0.9 = P(|Z|$

For a confidence level of 90% our $Z_{critic}$ is 1.645

Therefore,

$\frac{0.1}{\frac{\sigma}{\sqrt{n}}} = 1.645$

Substituting for $\sigma = 5$ and re-arrange for n, we have that n is equal to

$n=(\frac{1.645\sigma}{0.1})^2$

$n=\frac{(1.645)^2(0.5)^2}{0.1^2}$

$n=67.65$

$n=68$

We need to make 68 readings for have a probability of 90% and our average is within $0.1\°\frac$

3 0

2 years ago

The motion of a particle is defined by the relation x 5 t 3 2 9t 2 1 24t 2 8, where x and t are expressed in inches and seconds,

shutvik [7]

Answer:

a) t = 2.0 s, b) x_f = - 24.56 m, Δx = 16.56 m

Explanation:

This is an exercise in kinematics, the relationship of position and time is indicated

x = 5 t³ - 9t² -24 t - 8

a) ask when the velocity is zero

speed is defined by

v = $\frac{dx}{dt}$

let's perform the derivative

v = 15 t² - 18t - 24

0 = 15 t² - 18t - 24

let's solve the quadratic equation

$t = \frac{18 \pm \sqrt{18^2 + 4 \ 15 \ 24} }{2 \ 15}$

t = $\frac{18 \pm 42}{30}$

t1 = -0.8 s

t2 = 2.0 s

the time has to be positive therefore the correct answer is t = 2.0 s

b) the position and distance traveled for a = 0

acceleration is defined by

a = dv / dt

a = 30 t - 18

a = 0

30 t = 18

t = 18/30

t = 0.6 s

we substitute this time in the expression of the position

x = 5 0.6³ - 9 0.6² - 24 0.6 - 8

x = 1.08 - 3.24 - 14.4 - 8

x = -24.56 m

we see that all the movement is in one dimension so the distance traveled is the change in position between t = 0 and t = 0.6 s

the position for t = 0

x₀ = -8 m

the position for t = 0.6 s

x_f = - 24.56 m

the distance

ΔX = x_f - x₀

Δx = | -24.56 -(-8) |

Δx = 16.56 m

5 0

2 years ago