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3 years ago

What do you think that astronomers mean when they use the term observable universe?

1 answer:

6 0

The observable universe consists of galaxies and other matter that can, principally, be seen from Earth because the light signals have had time to reach us. Not everything in the sky is the way it is when we see it, because of the distance the light travels to reach us.

Hope this helps :)

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A set of four capacitors are attached to a 12V battery in the circuit shown below. All capacitances are measured in milli-Farads

Bond [772]

The amount of electric charge that resides on each capacitor once it is fully charged is 0.37 C.

<h3>Total capacitance of the circuit</h3>

The total capacitance of the circuit is calculated as follows;

Capacitors in series;

1/Ct = 1/8 + 1/7.5

1/Ct = 0.25833

Ct = 3.87 mF

Capacitors is parallel;

Ct = 3.87 mF + 12 mF + 15 mF

Ct = 30.87 mF

Ct = 0.03087 F

<h3>Charge in each capacitor</h3>

Q = CV

Q = 0.03087 x 12

Q = 0.37 C

Thus, the amount of electric charge that resides on each capacitor once it is fully charged is 0.37 C.

Learn more about capacitors here: brainly.com/question/13578522

#SPJ1

3 0

2 years ago

Students are given the following information about a 2.0 kg, motorized toy boat on water. what net force is exerted on the boat

Natasha_Volkova [10]

The motorized toy boat experiences a net force of 0 N between 4 s and 8 s.

The motorized toy boat moves at 8 m/s (u) at 4 s and at 8 m/s (v) at 8 s. We can calculate the acceleration (a) in that period using the following kinematic expression.

$a = \frac{v-u}{\Delta t} = \frac{8m/s-8m/s}{8s-4s} = 0 m/s^{2}$

The object with a mass (m) of 2.0 kg experiences an acceleration of 0 m/s². We can calculate the net force (F) in that period using Newton's second law of motion.

$F = m \times a = 2.0 kg \times 0 m/s^{2} = 0 N$

The motorized toy boat experiences a net force of 0 N between 4 s and 8 s.

Learn more: brainly.com/question/13447525

6 0

3 years ago

an ice skater starts with a velocity 2.25 m/s in a 50.0 degree direction after 8.33s she is moving 4.65 m/s in a 120 degree dire

svetoff [14.1K]

Answer:

$-0.032 m/s^2$

Explanation:

To answer the question, we just need to consider the motion along the horizontal direction.

The component of the initial velocity of the ice skater along the x-direction is:

$u_x = u cos \theta =(2.25)(cos 50^{\circ})=1.45 m/s$

where u = 2.25 m/s is the initial velocity and $50^{\circ}$ is the angle.

The component of the final velocity of the ice skater along the x-direction is

$v_x = u cos \theta =(4.65)(cos 120^{\circ})=-2.33 m/s$

where u = 4.65 m/s is the final velocity and $120^{\circ}$ is the angle.

The acceleration along the x-direction is given by

$a_x=\frac{v_x-u_x}{t}$

where

t = 120 s is the time

Substituting,

$a=\frac{-2.33-(1.45)}{120}=-0.032 m/s^2$

7 0

4 years ago

A crane raises a 12,000 N marble sculpture at a constant velocity onto a pedestal 1.5 m above the ground outside an art museum.

Simora [160]

For the work, applicate formula:

$\boxed{\boxed{\green{\bf{W = F\times d}}}}$

According our data:

Replacing:

W = 12000 N * 1,5 m

Resolving:

W = 18000 J

The work done is <u>18000 Joules.</u>

7 0

3 years ago

Two cars collide inelastically and stick together after the collision. Before the collision, the magnitudes of their momenta are

slavikrds [6]

Answer:

The correct answer is

p = p₁ + p₂

Explanation:

Newton's second law states that force = the change of momentum produced therefore since the collision is inelstic then the change of momentum of each car is p₁ and p₂ and the force of the collition is proportional to p₁ + p₂ that is

F ∝ p₁ + p₂ and since force is directly proportional to p we have

p = p₁ + p₂

7 0

4 years ago