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taurus [48]
3 years ago
11

A radio signal has a frequency of 1.023 x 108 HZ. If the speed of the signal in air is 2.997 x 108m/s, what is the wavelength of

the signals? а 7.15 m b 5.23 m C 2.93 m d 0.93 m​
Physics
1 answer:
Sladkaya [172]3 years ago
5 0

Answer:

2.93 m  (which agrees with answer "C" on the list)

Explanation:

Recall that the speed of the wave equals the product of the wave's length times its frequency. Therefore, the wavelength is going to be the quotient of the speed of the signal divided its frequency:

Wavelength = 2.997  10^8 / 1.023  10^8 =  2.93 m

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Genrish500 [490]
The work of Brian mind interface is to learn that’s my guess lol
4 0
4 years ago
A stuntman with a mass of 82.5 kg swings across a pool of water from a rope that is 12.0 m. At the bottom of the swing the stunt
Brilliant_brown [7]

Answer:

The stuntman will not make it

Explanation:

At the bottom of the swing, the equation of the forces acting on the stuntman is:

T-mg = m\frac{v^2}{r}

where:

T is the tension in the rope (upward)

mg is the weight of the man (downward), where

m = 82.5 kg is his mass

g=9.8 m/s^2 is the acceleration due to gravity

m\frac{v^2}{r} is the centripetal force, where

v = 8.65 m/s is the speed of the man

r = 12.0 m is the radius of the circule (the length of the rope)

Solving for T, we find the tension in the rope:

T=mg+m\frac{v^2}{r}=(82.5)(9.8)+(82.5)\frac{8.65^2}{12.0}=1322 N

Since the rope's breaking strength is 1000 N, the stuntman will not make it.

4 0
3 years ago
A 1500-kg car doubles its speed from 50 km/h to 100 km/h. By how many times does the kinetic energy from the car's forward motio
Marat540 [252]

Answer:

The kinetic energy increases 4 times

Explanation:

Given,

The mass of the car, m = 1500 Kg

The speed of the car doubles from 50 Km/h to 100 Km/h

The kinetic energy at 50 Km/h

                                K.E = ½mv²

                                       = ½ x 1500 x 50²

                                       = 1875000 J

The kinetic energy of the car at 100 Km/h

                               K.E = ½mv²

                                     = ½ x 1500 x 100²

                                     = 7500000 J

Hence, the final K.E is 4 times the initial K.E

6 0
3 years ago
A 500-g lump of clay is dropped onto a 1-kg cart moving at 60 cm/s. The clay is moving downward at 30 cm/s just before l dith t
viktelen [127]

Answer:

The speed of the cart and clay after the collision is 50 cm/s .

Explanation:

Given :

Mass of lump , m = 500 g = 0.5 kg .

Velocity of lump , v = 30 cm/s .

Mass of cart , M = 1 kg .

Velocity of cart , V = 60 cm/s .

We know by conservation of momentum :

mv+MV=(m+M)v'

Here , v' is the speed of the cart and clay after the collision .

Putting all value in above equation .

We get :

0.5\times 30+1\times 60=(0.5+1)\times v'\\\\v'=\dfrac{15+60}{1.5}\\\\v'=50\ cm/s

Hence , this is the required solution .

3 0
3 years ago
Because of barriers and obstructions you can see only a tiny fraction of a standing wave on a string. You do not know, for insta
REY [17]

Answer:

Sure, the frequency is 500Hz

Explanation:

Sure, the frequency can be calculated. The needed information which is the speed and wavelength of the wave are known.

Wavelength is the distance between two successive crest and trough of a wave.

Using the relationship

V = fλ

V is the speed of wave

F is the frequency

λ is the wavelength

f = v/λ

Given v = 100m/s, λ = 10cm/0.5 = 20cm

20cm = 0.2m

f = 100/0.2

f = 500Hertz

7 0
3 years ago
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