Please Help.....................................................

What is the area of a shape with points a 5 -8 b 11, -8 c 11,0 d 6,-3 e 4,-3

Dmitriy789 [7]

Answer:

Area of the given figure is 51.5 square units.

Step-by-step explanation:

Area of rectangle OCBH = Length × width

= 11 × 8

= 88 square units

Area of trapezoid OGEF = $\frac{1}{2}(b_1+b_2)\times h$

= $\frac{1}{2}(\text{GE+OF)}\times (\text{OG})$

= $\frac{1}{2}(3+6)\times 4$

= 18 units²

Area of trapezoid GCDE = $\frac{1}{2}(\text{GC+DE)}\times (\text{GE})$

= $\frac{1}{2}(7+2)\times 3$

= 13.5 units²

Area of triangle AFH = $\frac{1}{2}(\text{Base})\times (\text{Height})$

= $\frac{1}{2}(5)(2)$

= 5 units²

Area of polygon ABCDEF = Area of rectangle CBHO - (Area of trapezoid OGEF + Area of trapezoid GCDE + Area of triangle AFH)

= 88 - (18 + 13.5 + 5)

= 88 - 36.5

= 51.5 units²

Therefore, area of the given polygon is 51.5 units²

3 0

4 years ago

1-z/z-7 - 8z-3/7-z subtract

maxonik [38]

The answer to your question above would be: 7z-2/z-7

3 0

3 years ago

A perpendicular bisector intersects line segment A C at point B. The bisector also contains points E and D. Line segment A B is

sdas [7]

Answer:

(C)26 units

Step-by-step explanation:

Since point B bisects AC into two equal parts

AB=BC

Since the two right triangles have side BD in common, we can then say that the two triangles are congruent and the length of the hypotenuses (AD and DC) are equal.

If AD=DC

8x-1=6x+9

8x-6x=9+1

2x=10

x=5

Now,

AB=3x-2

=3(5)-2

=13 Units

Since AB=BC

AC=AB+BC

=13+13

AC=26 units

The measure of AC is 26 units.

7 0

4 years ago

Read 2 more answers

What is an equation for the line that passes through (-2,-3) with a slope of -1/2?

Crazy boy [7]

Answer:

C

Step-by-step explanation:

To write the equation of a line use the point slope form of a line substituting m = -1/2 and the point (-2,-3).

$y -y_1 = m(x-x_1)\\y --3=-\frac{1}{2}(x--2)\\y+3 = -\frac{1}{2}(x+2)$

Convert to standard form by applying the distributive property and rearranging the terms.

$y + 3 = -\frac{1}{2}(x+2)\\y+3 = -\frac{1}{2}x -1\\2y + 6 = -x -2\\x+2y + 6 = -2\\x + 2y = -8$

The equation x +2y = -8 is the same equation as 4y + 2x = -16 just doubled----> 2x + 4y = -16

8 0

3 years ago

Which equation represents a circle that contains the point (-5, -3) and has a center at (-2, 1)?

Evgen [1.6K]

The equation (x + 2)² + (y - 1)² = 25 represents a circle that contain the point (-5 , -3) and has a center at (-2 , 1)

Step-by-step explanation:

The equation of a circle of center (h , k) and radius r is:

(x - h)² + (y - k)² = r²

The given is:

The center of the circle is (-2 , 1)
The circle passes through point (-5 , -3)

The length of the radius is the distance from the center of the circle

to a point on the circle

∵ The formula of the distance is $d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$

∵ The center of the circle is (-2 , 1)

∵ The circle passes through point (-5 , -3)

∴ $r=\sqrt{[(-5)-(-2)]^{2}+[(-3)-(1)]^{2}}$

∴ $r=\sqrt{[-3]^{2}+[-4]^{2}}$

∴ $r=\sqrt{9+16}$

∴ $r=\sqrt{25}$

∴ r = 5

∵ The equation of the circle is (x - h)² + (y - k)² = r²

∵ The center of the circle is (-2 , 1)

∴ h = -2 and k = 1

∵ r = 5

∴ r² = (5)² = 25

- Substitute the values of h , k , r² in the equation of the circle

∴ (x - -2)² + (y - 1)² = 25

∴ (x + 2)² + (y - 1)² = 25

The equation (x + 2)² + (y - 1)² = 25 represents a circle that contains

the point (-5 , -3) and has a center at (-2 , 1)

Learn more:

You can learn more about the equation of the circle in brainly.com/question/9510228

LearnwithBrainly

7 0

3 years ago